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VARVARA [1.3K]
4 years ago
15

How to solve 3.13,? a,b

Mathematics
1 answer:
aliina [53]4 years ago
3 0
Your answer will be b
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Neil goes to the pet shop and
umka2103 [35]

Answer:

b (1/15)

Step-by-step explanation:

6 0
3 years ago
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Jim Ross is an automobile salesman who receives a salary of $500 per week plus a commission of 3% on all sales. During a four-we
mezya [45]
4 * 500 = $2,000 

<span>Then, you must calculate how much he earned by the commission: </span>

<span>$42,000 * 3% </span>

<span>(3% = 3/100) </span>

<span>42,000 * 3/100 = 420 * 3 = $1260 </span>

<span>Finally, you add what he earned form the commission plus the 4 weeks salary: </span>

<span>$2,000 + $1260 = $3,260</span>
3 0
4 years ago
Let u=ln x and v = ln y. Write ln y^7/x^5 in terms of u and v.
-BARSIC- [3]

\bf \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad a^{log_a x}=x\qquad \leftarrow \textit{we'll use this one} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ u=\ln(x)\implies u=\log_e(x)\implies e^u=e^{\log_e(x)}\implies \boxed{e^u=x} \\\\[-0.35em] ~\dotfill\\\\ v=\ln(y)\implies v=\log_e(y)\implies e^v=e^{\log_e(y)}\implies \boxed{e^v=y} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{y^7}{x^5}\implies \cfrac{(e^v)^7}{(e^u)^5}\implies \cfrac{e^{7v}}{e^{5u}}\implies e^{7v}\cdot e^{-5u}\implies e^{7v-5u}

6 0
3 years ago
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Inverse function of y=1-x/7
Romashka-Z-Leto [24]

Answer:

x = (7,0)

y = (0,1)

Step-by-step explanation:

4 0
3 years ago
What is y= 1/3x+2 equal to as a slope?
ArbitrLikvidat [17]

Answer:

The graph below models the value of a $20,000 car t years after it was purchased.

                    Value of Car

A graph titled Value of Car has years  bbhvb ngc,jon the x-axis and Dollars on the y-axis. A line curves down and goes through points (0, 20,000), (4, 10,000), and (14, 2,000).

Which statement best describes why the value of the car is a function of the number of years since it was purchased?

Each car value, y, is associated with exactly one time, t.

Each time, t, is associated with exactly one car value, y.

The rate at which the car decreases in value is not constant.

There is no time, t, at which the value of the car is 0.

Step-by-step explanation:

5 0
4 years ago
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