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FromTheMoon [43]
3 years ago
14

An automobile gasoline tank holds 42 kg of gasoline. When the gasoline burns, 168 kg of oxygen are consumed and carbon dioxide a

nd water are produced. What total combined mass of carbon dioxide and water is produced?
Chemistry
1 answer:
Georgia [21]3 years ago
5 0

Answer:

210 kg

Explanation:

The chemical reaction will look like this:

gasoline + O₂ (oxygen) → CO₂ (carbon dioxide) + H₂O (water) + heat

Now in chemical reactions the quantity of the reactants (gasoline + oxygen) is equal to the quantity of products (carbon dioxide + water), so from this principle we may determine:

combined mass of carbon dioxide and water produced = mass of gasoline + mass of oxygen

combined mass of carbon dioxide and water produced = 42 + 168  = 210 kg

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Dima020 [189]
The correct answer is b hope this helps air
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2 years ago
In which reaction does the oxidation number of hydrogen change? In which reaction does the oxidation number of hydrogen change?
dedylja [7]

<u>Answer:</u> The correct answer is 2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)

<u>Explanation:</u>

Oxidation number is defined as the number which is given to an atom when it looses or gains electron. When an atom looses electron, it attains a positive oxidation state. When an atom gains electron, it attains a negative oxidation state.

Oxidation state of the atoms in their elemental state is considered as 0. Hydrogen is present as gaseous state.

For the given chemical reactions:

  • <u>Reaction 1:</u>  2HClO_4(aq.)+CaCO_3(s)\rightarrow Ca(ClO_4)_2(aq.)+H_2O(l)+CO_2 (g)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

  • <u>Reaction 2:</u>  CaO(s)+H_2O(l)\rightarrow Ca(OH)_2(s)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

  • <u>Reaction 3:</u>  HCl(aq.)+NaOH(aq.)\rightarrow NaCl(aq.)+H_2O(l)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

  • <u>Reaction 4:</u>  2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: 0

Thus, the oxidation state of hydrogen is changing.

  • <u>Reaction 5:</u>  SO_2(g)+H_2O(l)\rightarrow H_2SO_3(aq.)

Oxidation state of hydrogen on reactant side: +1

Oxidation state of hydrogen on product side: +1

Thus, the oxidation state of hydrogen is not changing.

Hence, the correct answer is 2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)

6 0
3 years ago
Determine the boiling point of water at 620 mm Hg?
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7 0
3 years ago
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The answer would be kinetic energy. :)
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What Period would this element be in?
AlladinOne [14]

Answer:

Period 2

Explanation:

From the picture provided, I am guessing this is Fluorine. Normal Fluorine has 9 protons, electrons, and atomic number. Thus, it can be found in the second period.

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