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Soloha48 [4]
3 years ago
9

Which of the following is an extraneous solution of (45-3x)^1/2=x-9?

Mathematics
2 answers:
Alisiya [41]3 years ago
5 0

Answer:

The answer is C: X = 3

Step-by-step explanation:


JulsSmile [24]3 years ago
4 0

Answer:

An extraneous solution of the given expression is 3 and 12.

Step-by-step explanation:

Given : Expression (45-3x)^{\frac{1}{2}}=x-9

To find : An extraneous solution of given expression ?

Solution :

First we solve the given expression algebraically,

(45-3x)^{\frac{1}{2}}=x-9

Squaring both side,

(45-3x)^{\frac{2}{2}}=(x-9)^2

45-3x=x^2-18x+81

x^2-18x+81-45+3x=0

x^2-15x+36=0

Solving quadratic equation,

x^2-3x-12x+36=0

x(x-3)-12(x-3)=0

(x-3)(x-12)=0

x=3 \text{ or } x=12

Therefore, An extraneous solution of the given expression is 3 and 12.

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Archy [21]

The value of integration of y=16-x^{2} from x=-1 to x=1 is 94/3.

Given the equation y=16-x^{2} and the limit of the integral be x=-1,x=1.

We are required to find the value of integration of y=16-x^{2} from x=-1 to x=1.

Equation is relationship between two or more variables that are expressed in equal to form.Equation of two variables look like ax+by=c.It may be linear equation, quadratic equation, or many more depending on the power of variable.

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Find the integration of 16-x^{2}.

=16x-x^{3}/3

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