I got D.
There's a few ways to solve it; I prefer using tables, but there are functions on a TI-84 that'll do it for you too. The logic here is, you have a standard normal distribution which means right away, the mean is 0 and the standard deviation is 1. This means you can use a Z table that helps you calculate the area beneath a normal curve for a range of values. Here, your two Z scores are -1.21 and .84. You might notice that this table doesn't account for negative values, but the cool thing about a normal distribution is that we can assume symmetry, so you can just look for 1.21 and call it good. The actual calculation here is:
1 - Z-score of 1.21 - Z-score .84 ... use the table or calculator
1 - .1131 - .2005 = .6864
Because this table calculates areas to the RIGHT of the mean, you have to play around with it a little to get the bit in the middle that your graph asks for. You subtract from 1 to make sure you're getting the area in the middle and not the area of the tails in this problem.
To find the slope you rise before you run and if you can't rise then you go downwards so it would be down -3 over positive 2
Answer: No, because the line does not touch any points.
Step-by-step explanation:
A line of best fit should pass through most if not all of the points on a graph. If it does not, it can't be considered a line of best fit.
Answer:
A a line
Step-by-step explanation:
x-y= 4
is the form of ax+by+c=0 so it is linear function and the graph is a line
Answer:
- ABC -- not similar
- ΔJKL ~ ΔHIG, AA similarity
- not similar
Step-by-step explanation:
a) Side ratios in the smaller triangle are 3:4:6. In the larger triangle, they are 5:6:9. These are not equivalent ratios, so the triangles are <em>not similar</em>.
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b) The missing angle in the left triangle is 90° -55° = 35°. This matches the acute angle shown in the right triangle, so the right triangles are similar by the AA similarity criterion. The given triangle JKL starts with the largest acute angle, then the right angle, so the similarity statement must be ...
ΔJKL ~ ΔHIG
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c) All we know for sure is that the vertical angles are congruent. We need information about a pair of sides or of another angle before any similarity can be claimed. The triangles are <em>not necessarily similar</em>.
