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ivanzaharov [21]
3 years ago
12

is picking out some movies to rent, and he has narrowed down his selections to 5 documentaries, 7 comedies, 4 mysteries, and 5 h

orror films. How many different combinations of 9 movies can he rent if he wants all 7 comedies?
Mathematics
1 answer:
pogonyaev3 years ago
5 0

Answer: 91

Step-by-step explanation:

Given : The number of documentaries = 5

The number of comedies = 7

The number of mysteries = 4

The number of horror films =5

The total number of movies other than comedy = 14

Now, the number of possible combinations of 9 movies can he rent if he wants all 7 comedies is given by :-

^7C_7\times^{14}C_2\\\\\dfrac{7!}{7!(7-7)!}\times\dfrac{14!}{2!(14-2)!}\\\\=(1)\times\dfrac{14\times13}{2}\\\\=91

Therefore, the number of possible combinations of 9 movies can he rent if he wants all 7 comedies is 91 .

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Answer:

The\ simplified\ form\ of\ the\ \frac{5 + 6i}{4 + 6i}\ is\ \frac{56-6i}{52}.

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Step-by-step explanation:

As the expression given in the question as follows.

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Now rationalize the expression.

= \frac{5 + 6i\times 4 - 6i}{4 + 6i\times 4 - 6i}

Using the formula

a² - b² = (a - b) (a + b)

Using in the above

= \frac{5 + 6i\times 4 - 6i}{(4)^{2} - (6i)^{2}}

= \frac{5\times 4-5\times 6i+6i\times 4-36\ i^{2}}{16 - 36(i)^{2}}

As i² = -1

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