9514 1404 393
Answer:
{Segments, Geometric mean}
{PS and QS, RS}
{PS and PQ, PR}
{PQ and QS, QR}
Step-by-step explanation:
The three geometric mean relationships are derived from the similarity of the triangles the similarity proportions can be written 3 ways, each giving rise to one of the geometric mean relations.
short leg : long leg = SP/RS = RS/SQ ⇒ RS² = SP·SQ
short leg : hypotenuse = RP/PQ = PS/RP ⇒ RP² = PS·PQ
long leg : hypotenuse = RQ/QP = QS/RQ ⇒ RQ² = QS·QP
I find it easier to remember when I think of it as <em>the segment from R is equal to the geometric mean of the two segments the other end is connected to</em>.
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segments PS and QS, gm RS
segments PS and PQ, gm PR
segments PQ and QS, gm QR
this now rhe answer
(123+2"51=?=90.356821.2344
Answer:
cab=62
cba=48
x=12
Step-by-step explanation:
70+x+50+4x=180
combine like terms
120+5x=180
-120. -120
5x= 60
isolate x
5x=60
x=12
Answer:
V≈278.85
Step-by-step explanation:
AB=s(s﹣a)(s﹣b)(s﹣c)
V=ABh
s=a+b+c
2
Solving forV
V=1
4h﹣a4+2(ab)2+2(ac)2﹣b4+2(bc)2﹣c4=1
4·8·﹣64+2·(6·12)2+2·(6·12)2﹣124+2·(12·12)2﹣124≈278.8548
15, 20, and 25 are a Pythagorean triple, (225+40=625) thus they form a right triangle. The shortest altitude of any right triangle is going to be that of the hypotenuse. All three of the right triangles formed by the altitude on hypotenuse are similar. Thus 15:25 = a:10.
a=6.
