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Mathematics

1 answer:

Leya [2.2K]3 years ago

8 0

Please mark brainliest!!

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Consider the input and output values for f(x) = 2x - 3 and g(x) = 2x + 7. What is a reasonable explanation for different rules w

Dahasolnce [82]

it’s A the multiple

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3 years ago

Read 2 more answers

3x^2 – 8x + 5 = 5x^2

Ghella [55]

Answer:

Step-by-step explanation:

$3x^2 -8x +5 = 5x^2\\\\5x^2 - 3x^2 + 8x -5 =0\\\\2x^2 +8x -5 = 0\\\\$

a = 2, b = 8, c = -5

$x = \frac{-b \pm \sqrt{b^2 -4ac} }{2a}\\\\x = \frac{-8 \pm \sqrt{8^2 - ( 4 \times 2 \times (-5))} }{2 \times 2}\\\\x = \frac{-8 \pm \sqrt{64 +40} }{4}\\\\x = \frac{-8 + \sqrt{64 +40} }{4} \ , \ x = \frac{-8 - \sqrt{64 +40} }{4}\\\\x = \frac{-8 + \sqrt{104} }{4} \ , \ x = \frac{-8 - \sqrt{104} }{4}\\\\x = \frac{-8 + \sqrt{4 \times 26} }{4} \ , \ x = \frac{-8 - \sqrt{4 \times 26} }{4}\\\\x = \frac{-8 +2 \sqrt{26} }{4} \ , \ x = \frac{-8 - 2\sqrt{26} }{4}\\\\$

$x = \frac{-4 + \sqrt{26} }{2} \ , \ x = \frac{-4 - \sqrt{26} }{2}$

8 0

3 years ago

A farmer owns chickens and sheep. One day, he observed that when his animals were all together, there were at least 30 legs but

motikmotik

Answer:

c+s < 12, 2c+4s >= 30.

Step-by-step explanation:

Known: at least 30 legs, less than 12 heads.

Each animal has one head, so if there are less than 12 heads, then c + s < 12.

Sheep have four legs and chickens have two legs, so if there are at least 30 legs, then # of chicken legs + # of sheep legs >= 30, ----> c(2) + s(4) >= 30, ----> 2c + 4s >= 30.

The graph attached models the problem is you set the x axis as "c" (# of chickens) and y axis as "s" (# of sheep).