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fomenos
1 year ago
6

The city has an average of 13 days of rainfall for April.

Mathematics
1 answer:
zhenek [66]1 year ago
6 0

Using the Poisson distribution, we have that:

  • There is a 0.0859 = 8.59% probability of having exactly 10 days of precipitation in the month of April.
  • There is a 0.00022 = 0.022% probability of having less than three days of precipitation in the month of April.
  • There is a 0.2364 = 23.64% probability of having more than 15 days of precipitation in the month of April.

<h3>What is the Poisson distribution?</h3>

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

The parameters are:

  • x is the number of successes
  • e = 2.71828 is the Euler number
  • \mu is the mean in the given interval.

For this problem, the mean is given as follows:

\mu = 13

The probability of having exactly 10 days of precipitation in the month of April is P(X = 10), hence:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

P(X = 10) = \frac{e^{-13}13^{10}}{(10)!} = 0.0859

There is a 0.0859 = 8.59% probability of having exactly 10 days of precipitation in the month of April.

The probability of having less than three days of precipitation in the month of April is:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which:

P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-13}13^{0}}{(0)!} \ approx 0

P(X = 1) = \frac{e^{-13}13^{1}}{(1)!} = 0.00003

P(X = 2) = \frac{e^{-13}13^{2}}{(2)!} = 0.00019

Then:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0 + 0.00003 + 0.00019 = 0.00022

There is a 0.00022 = 0.022% probability of having less than three days of precipitation in the month of April.

For more than 15 days, the probability is:

P(X > 15) = P(X = 16) + P(X = 17) + ... + P(X = 20)

Applying the formula for each of these values and adding them, we have that P(X > 15) = 0.2364, hence:

There is a 0.2364 = 23.64% probability of having more than 15 days of precipitation in the month of April.

More can be learned about the Poisson distribution at brainly.com/question/13971530

#SPJ1

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Answer:

The diagram of the plotting point \left(3\frac{1}{2},\:2\frac{3}{4}\right)=\left(3.5,\:2.75\right) is attached below.

Step-by-step explanation:

Given the points

\left(3\frac{1}{2},\:2\frac{3}{4}\right)

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\left(3\frac{1}{2},\:2\frac{3}{4}\right)=\left(3.5,\:2.75\right)

Now, we can check the point x = 3.5, and determine the corresponding value y = 2.75 and plot the point at the location (x, y) = (3.5, 2.75)

The diagram of the plotting point \left(3\frac{1}{2},\:2\frac{3}{4}\right)=\left(3.5,\:2.75\right) is attached below.

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G

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Using the rule of exponents

\frac{a^{m} }{a^{n} } = a^{m-n}

Consider the left side

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Answer:

total people = X = 200

Step-by-step explanation:

total people = X = 200

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Percent haing experience = 40 % = 40 / 100

40/ 100  x X = 80

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For this case we must simplify the following expression:

x ^ 2-3xy-5xy-7y ^ 2 + 4x ^ 2 + 8y ^ 2

We must add similar terms taking into account that:

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