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Masteriza [31]
3 years ago
10

You might need: Calculator The organizers of a mentoring program are curious about whether there are differences in outcomes whe

n the gender of the mentor matches the young adult mentee. They take separate random samples of 80 young adults with either the same-gender or different-gender mentors to see the difference between the sample proportions (ps PD.). Suppose that 90% of young adults with same-gender mentors get jobs while 84% different-gender mentors get jobs​
Mathematics
1 answer:
Nady [450]3 years ago
6 0

Answer:

Not Normal, because we expect fewer than 10 young adults without jobs with same gender

Step-by-step explanation:

khan

You might be interested in
I need help ASAP! Can anyone please check my work?
STALIN [3.7K]

A = event the person got the class they wanted

B = event the person is on the honor roll

P(A) = (number who got the class they wanted)/(number total)

P(A) = 379/500

P(A) = 0.758

There's a 75.8% chance someone will get the class they want

Let's see if being on the honor roll changes the probability we just found

So we want to compute P(A | B). If it is equal to P(A), then being on the honor roll does not change P(A).

---------------

A and B = someone got the class they want and they're on the honor roll

P(A and B) = 64/500

P(A and B) = 0.128

P(B) = 144/500

P(B) = 0.288

P(A | B) = P(A and B)/P(B)

P(A | B) = 0.128/0.288

P(A | B) = 0.44 approximately

This is what you have shown in your steps. This means if we know the person is on the honor roll, then they have a 44% chance of getting the class they want.

Those on the honor roll are at a disadvantage to getting their requested class. Perhaps the thinking is that the honor roll students can handle harder or less popular teachers.

Regardless of motivations, being on the honor roll changes the probability of getting the class you want. So Alex is correct in thinking the honor roll students have a disadvantage. Everything would be fair if P(A | B) = P(A) showing that events A and B are independent. That is not the case here so the events are linked somehow.

8 0
3 years ago
Which property is not a characteristic of a parallelogram?
ratelena [41]

Answer:

B

Step-by-step explanation:

8 0
3 years ago
Which of these is closest in size to 1?<br> 0.95<br> 1.05<br> 0.960<br> 1.040<br> 0.95
yuradex [85]
1.05....................
8 0
2 years ago
How many times greater is<br> 3.8 x 105<br> than<br> 1.9 X 1022<br> 2<br> 20<br> 200<br> 2000
PilotLPTM [1.2K]

Step-by-step explanation:

there must be something wrong with your text.

what we can see is

3.8 × 105

and

1.9 × 1022

the true answer for these values has nothing to do with the 4 answer options.

maybe you meant

1.9 × 10.5 ?

because that answer would be 20.

but first working with the presented numbers :

3.8 × 105 = 399

1.9 × 1022 = 1941.8

so, the second number is actually much bigger than the first number.

but if it is

1.9 × 10.5 = 19.95

that works.

and we can either use the calculator to calculate

399 / 19.95 = 20

or we can simply look at the factor changes of the multiplication terms.

3.8 = 1.9 × 2

105 = 10.5 × 10

so, the multiplication product of the two larger numbers is then 2×10=20 times larger than the product of the 2 smaller numbers.

7 0
3 years ago
Use the equation a = IaIâ
german

Answer:

a) \:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }

b)\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }

c) \:\:=7\cdot \frac{\:\:}{7}

Step-by-step explanation:

a) Let <u>a</u>=<2,1,-3>

The magnitude of <u>a</u> is |a|=\sqrt{2^2+1^2+(-3)^2}

|a|=\sqrt{4+1+9}=\sqrt{14}

The unit vector in the direction of a is

\hat{a}=\frac{\:\:}{\sqrt{14} }

Using the relation a=|a|\hat{a}, we have

\:\:=\sqrt{14}\cdot \frac{\:\:}{\sqrt{14} }

b) Let a=2i - 3j + 4k

|a|=\sqrt{2^2+(-3)^2+4^2}

|a|=\sqrt{4+9+16}=\sqrt{29}

\hat{a}=\frac{\:\:}{\sqrt{29} }

Using the relation a=|a|\hat{a}, we have

\:\:=\sqrt{29} \cdot \frac{\:\:}{\sqrt{29} }

c) Let us first find the sum of <1, 2, -3> and <2, 4, 1> to get:

<1+2, 2+4, -3+1>=<3, 6, -2>

Let a=<3, 6, -2>

The magnitude is

|a|=\sqrt{3^2+6^2+(-2)^2}

|a|=\sqrt{9+36+4}=\sqrt{49}=7

The unit vector in the direction of <u>a</u> is

\hat{a}=\frac{\:\:}{7}

Using the relation a=|a|\hat{a}, we have

\:\:=7\cdot \frac{\:\:}{7}

5 0
3 years ago
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