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Ludmilka [50]
3 years ago
8

2/10 + 6/100 = ? A: 8/10 B: 8/100 C: 26/10 D: 26/100

Mathematics
2 answers:
Ainat [17]3 years ago
5 0

Answer:

d

Step-by-step explanation:

Anestetic [448]3 years ago
4 0
2/10 = 20/100
20/100+ 6/100 = 26/100
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How many laps would 50 miles be on a 1/2 mile track?
Tanzania [10]

Answer:

100

Step-by-step explanation:

Multiply 50 by 2

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3 years ago
Select the three values of y that are solutions to y2=196
xz_007 [3.2K]

the answer is y= 14, -14

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3 years ago
What are the solutions of the equation x4−10x2+9=0? Use u substitution.
PSYCHO15rus [73]

Answer:

Step-by-step explanation:

X^4 - 10X^2 + 9 =0    This factors. It just looks odd.

(x^2 - 1)(x^2 - 9) = 0

x^2 - 1 = (x + 1)(x - 1) = 0

x = 1 and x = - 1

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7 0
3 years ago
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kotykmax [81]
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4 0
4 years ago
Orange traffic cones come in a variety of sizes. Approximate the volume, in cubic inches, of a traffic cone that has a height of
Irina18 [472]

Answer:

Volume of the cone = 628 cubic inches.

Step-by-step explanation:

Given:

Height of the traffic cone, h = 2 feet = 24 inches        ...[1 feet =12 inches]

Diameter of the cone, d = 10 inches

Radius of the cone, r = 5 inches                                  ...[r=\frac{d}{2}]

Value of pie, \pi = 3.14

We have to find the approximate volume.

Lets say that the volume is V .

Formula:

Volume of a cone = \frac{\pi r^2h}{3}

So,

⇒ V=\frac{\pi r^2h}{3}

⇒ Plugging the values.

⇒ V=\frac{3.14\times 5^2\times 24}{3}

⇒ V=\frac{3.14\times 25\times 24}{3}

⇒ V=628  inches^3

The volume of the orange traffic cone is 628 inches^3.

8 0
3 years ago
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