I've attached the complete question.
Answer:
Only participant 1 is not cheating while the rest are cheating.
Because only participant 1 has a z-score that falls within the 95% confidence interval.
Step-by-step explanation:
We are given;
Mean; μ = 3.3
Standard deviation; s = 1
Participant 1: X = 4
Participant 2: X = 6
Participant 3: X = 7
Participant 4: X = 0
Z - score for participant 1:
z = (x - μ)/s
z = (4 - 3.3)/1
z = 0.7
Z-score for participant 2;
z = (6 - 3.3)/1
z = 2.7
Z-score for participant 3;
z = (7 - 3.3)/1
z = 3.7
Z-score for participant 4;
z = (0 - 3.3)/1
z = -3.3
Now from tables, the z-score value for confidence interval of 95% is between -1.96 and 1.96
Now, from all the participants z-score only participant 1 has a z-score that falls within the 95% confidence interval.
Thus, only participant 1 is not cheating while the rest are cheating.
Answer:
the answer is -3
Step-by-step explanation:
1. add the -4 to 10 (-10 + 4)
2. -6= 2a
3. divide both sides by 2
4. -3= a
hope this helps
It should be A
Angle b=angle g
6x+8=4x+12
2x=4
1 gram = 1000 milligrams
a) You can pick any 3 <u>gram</u> numbers that add to 15.4 grams
For example, 5 , 3, 7.4 = 15.4 grams
a) You pick any 3 <u>milligram</u> numbers that add to 15.4 grams (or 154,000 milligrams)
For example, 50,000, 70,000, 34,000 = 154,000 milligrams
