Answer:
Step-by-step explanation:
If 
, then 
. It follows that
![\begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \cdot [g(x+h) - g(x)] \\&= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%20%5C%5C%5Cfrac%7Bg%28x%2Bh%29-g%28x%29%7D%7Bh%7D%20%26%3D%20%5Cfrac%7B1%7D%7Bh%7D%20%5Ccdot%20%5Bg%28x%2Bh%29%20-%20g%28x%29%5D%20%5C%5C%26%3D%20%5Cfrac%7B1%7D%7Bh%7D%20%5Cleft%28%20%5Cfrac%7B1%7D%7Bx%2Bh%7D%20-%20%5Cfrac%7B1%7D%7Bx%7D%20%5Cright%29%5Cend%7Baligned%7D)
Technically we are done, but some more simplification can be made. We can get a common denominator between 1/(x+h) and 1/x.
Now we can cancel the h in the numerator and denominator under the assumption that h is not 0.
Answer:
4
Step-by-step explanation:
Divide 28 by 7 and get 4.
Answer:
yes I think that's right because 14-12=26 so if you subtract 26 from 8 which that will give you 18
<span>Simplify: (d - 3)(d + 9)
A) d^2 + 6
B) d^2 - 27
C) d^2 - 12d - 27
D) d^2 + 6d - 27</span>
Hello:
3x²+5x+2=0
delta = (5)²-4(3)(2)=1
x =( -5 <span>±1)/6
x= -2/3 or x=-1
t4-81=(t²)² -9² = (t²-9)(t²+9) =(t-3)(t+3)(t²+9)....(answer B)</span>
