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2 years ago

8

In the united states, 40% of the population has brown eyes. if 14 people are randomly selected, find the probability that at mos

t 11 of them have brown eyes.

1 answer:

leonid [27]2 years ago

4 0

I think the answer is 11/35

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The sum of ∠X and ∠Y is 90°. Which statement is TRUE?

Nadya [2.5K]

Answer:

the answer is that both x and y are acute

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2 years ago

The angles in a triangle are in the ratio 1:2:3 show that this triangle is a right angle traingle

mojhsa [17]

Answer and explanation:

We know the sum of interior angles in a triangle is 180°.

1 : 2 : 3 = 6 (1 + 2 + 3)
x : y : z = 180 (x, y and z are the unknown angles)

To get from 6 to 180, we multiply by 30. This means we can find the angles by doing:

1 × 30 = 30°
2 × 30 = 60°
3 × 30 = 90°

The triangle must be right-angled because one of the angles is 90°. We know that the shape is a triangle because 30 + 60 + 90 = 180°.

The ratio is 30 : 60 : 90.

Hope this helps!

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2 years ago

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Rewrite the equation by completing the square.<br> 6 - 16 = 0<br> (x +

Nady [450]

Answer:

6-16=10x here is you answer

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3 years ago

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Graham wants to determine which football team is the most popular at a game between the home team and the visiting team. Which o

Schach [20]

I think that your answer the answer is A

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2 years ago

This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the ex

pashok25 [27]

Answer with Step-by-step explanation:

We are given that

$f(x,y,z)=10x+10y+3z$

$g(x,y,z)=5x^2+5y^2+3z^2=43$

We have to find the extreme values of the function.

$f_x(x,y,z)=10,f_y(x,y,z)=10,f_z(x,y,z)=3$

$g_x(x,y,z)=10x,g_y(x,y,z)=10y,g_z(x,y,z)=6z$

$\Delta f(x,y,z)=\lambda \Delta g(x,y,z)$

Therefore,

$10=\lambda 10x\implies x=\frac{1}{\lambda}$

$10=10y\lambda\implies y=\frac{1}{\lambda}$

$3=6z\lambda$

$z=\frac{1}{2\lambda}$

Substitute the values in g(x)

Then, we get

$\frac{5}{\lambda^2}+\frac{5}{\lambda^2}+\frac{3}{4\lambda^2}=43$

$\frac{20+20+3}{4\lambda^2}=43$

$\frac{43}{4\lambda^2}=43$

$\lambda^2=\frac{43}{4\times 43}$

$\lambda=\pm\frac{1}{2}$

When $\lambda=\frac{1}{2}$ then,

$x=2,y=2,z=1$

When $\lambda=-\frac{1}{2}$

Then, $x=-2,y=-2,z=-1$

$f(2,2,1)=10+10+3=23$

$f(-2,-2,-1)=-10-10-3=-23$

Hence, maximum value of f(x,y,z) is 23 at (2,2,1) and minimum value of f(x,y,z) is -23 at (-2,-2 ,-1).

8 0

3 years ago