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2 years ago

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In the united states, 40% of the population has brown eyes. if 14 people are randomly selected, find the probability that at mos

t 11 of them have brown eyes.

1 answer:

leonid [27]2 years ago

4 0

I think the answer is 11/35

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The height, h, of an object that is thrown upwards into the air can be represented as h = 0.5at2 + v0t + h0, where a represents

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ok so this awnser is v7a

Step-by-step explanation:

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2 years ago

Teresa placed parentheses in the expression below so that its value was greater than 80. Write the expression to show where Tere

AlexFokin [52]

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2 years ago

Y = 2(x – 4)– 6<br> Vertex:<br> y-intercept: _

serious [3.7K]

Answer:

vertex: (4,-6), y= -14

Step-by-step explanation:

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2 years ago

What is 27cm added to 1m 80cm

nikdorinn [45]

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2 years ago

Read 2 more answers

A research team at Cornell University conducted a study showing that approximately 10% of all businessmen who wear ties wear the

LenKa [72]

Answer:

a) The probability that at least 5 ties are too tight is P=0.0432.

b) The probability that at most 12 ties are too tight is P=1.

Step-by-step explanation:

In this problem, we could represent the proabilities of this events with the Binomial distirbution, with parameter p=0.1 and sample size n=20.

a) We can express the probability that at least 5 ties are too tight as:

$P(x\geq5)=1-\sum\limits^4_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\geq5)=1-(0.1216+0.2702+0.2852+0.1901+0.0898)\\\\P(x\geq5)=1-0.9568=0.0432$

The probability that at least 5 ties are too tight is P=0.0432.

a) We can express the probability that at most 12 ties are too tight as:

$P(x\leq 12)=\sum\limits^{12}_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\leq 12)=0.1216+0.2702+0.2852+0.1901+0.0898+0.0319+0.0089+0.0020+0.0004+0.0001+0.0000+0.0000+0.0000\\\\P(x\leq 12)=1$

The probability that at most 12 ties are too tight is P=1.

5 0

2 years ago