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mafiozo [28]
3 years ago
14

. Determine whether the forces in the pair are pulling at right angles to each other. For each group of three forces below, dete

rmine whether the forces in each pair are pulling at right angles to each other. 13 lb, 35 lb, resultant force 30 lb no; 20 lb, 15 lb, resultant force 25 lb yes 13 lb, 35 lb, resultant force 30 lb yes; 20 lb, 15 lb, resultant force 25 lb yes 13 lb, 35 lb, resultant force 30 lb yes; 20 lb, 15 lb, resultant force 25 lb no 13 lb, 35 lb, resultant force 30 lb no; 20 lb, 15 lb, resultant force 25 lb no
Mathematics
1 answer:
Marat540 [252]3 years ago
3 0

Answer:

13lb

Step-by-step explanation:

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Answer:

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S=a1/1-r
valentinak56 [21]

Answer:

4

Step-by-step explanation:

This is an <em>infinite geometric series</em>. This has a sum of  \frac{a}{1-r}

Where

a is the first term, and

r is the common ratio (one term divided by the previous term)

Let's figure out the first 2 terms by plugging in n = 1 first and then n = 2 for the series.

<u />

<u>First term:</u>

3(\frac{1}{4})^{n-1}\\=3(\frac{1}{4})^{1-1}\\=3(\frac{1}{4})^0\\=3(1)\\=3

<u>Second term:</u>

3(\frac{1}{4})^{n-1}\\=3(\frac{1}{4})^{2-1}\\=3(\frac{1}{4})^1\\=3(\frac{1}{4})\\=\frac{3}{4}

<em>Let's see the common ratio:  \frac{\frac{3}{4}}{3}\\=\frac{3}{4}*\frac{1}{3}\\=\frac{1}{4}</em>

<em />

<em>Thus we have a = 3 and r = 1/4</em><em>. Plugging into the formula of the infinite sum, we get:</em>

<em>s=\frac{a}{1-4}=\frac{3}{1-\frac{1}{4}}=\frac{3}{\frac{3}{4}}=3*\frac{4}{3}=4</em>

<em />

<em>So, </em><em>the answer is 4</em>

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The average of 3,5,10 and X is 6, what is the value of X?
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The average of 4 numbers is 6, which means that (3 + 5 + 10 + x) all divided by 4 is 6. That means that 3 + 5 + 10 + x = 24, because 24/4 is 6.

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