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ehidna [41]
3 years ago
9

In PEMDAS we do Multiplication and Addition in the same step ?​

Mathematics
2 answers:
madreJ [45]3 years ago
8 0

Answer:

No

Step-by-step explanation:

Multiplication comes before addition and each letter of PEMDAS represents a step. Multiplication and addition are their own steps.

P-Parenthesis

E-Exponents

M-Multiplication

D-Division

A-Addition

S-Subtraction

laila [671]3 years ago
4 0

Answer:

no

Step-by-step explanation:

no you do multiplication and division in the same step then addition and subtraction

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A bag of tokens contains 9 red, 6 green, and 5​ blue tokens. What is the probability that a randomly selected token is red and g
german

Answer:

27/200

Step-by-step explanation:

Knowing that:

A bag of tokens contains 9 red, 6 green, and 5​ blue tokens. What is the probability that a randomly selected token is red and green?

Solve:

and = multiply

Total = 9 red + 6 green + 5 blue = 9 + 6 + 5 = 20

Total = 20 token

Thus,

There are 9 red and 6 green..

Hence,

9 out of 20 is red

6 out of 20 is green

Equation

9/20 × 6/20

Multiply Across:

9 × 6 = 54

20 × 20 = 400

54/400

Simplify

27/200

Therefore, the probability that a randomly selected token is red and green is 27/200.

<u><em>~Lenvy~</em></u>

6 0
2 years ago
Read 2 more answers
Hannah buys 2/3 pound of roast beef. She uses 1/4 pound to make sandwiches for lunch. How much roast beef does she have left?
Vanyuwa [196]
First we need to make both fractions equal to each other, and that means having to have the denominators the same.

What both 3 and 12 easily go into is 12.

So we need to make both fractions have a denominator of 12, so we multiply.

2/3 * 4/4 = 8 / 12

1/4 * 3/3 = 3 / 12

Now, we know that she has 8 / 12 pounds, and she uses 3 / 12 of it, so now we subtract to find how much she has left.

8 - 3 = 5

Out of the 12 pounds of roast beef, she now has 5 / 12 left.
7 0
3 years ago
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A student takes a multiple-choice test that has 11 questions. Each question has five choices. The student guesses randomly at ea
marissa [1.9K]

Answer:

a) P(6) = 0.0097

b) P(More than 3) = 0.1611

Step-by-step explanation:

For each question, there are only two possible outcomes. Either it is guessed correctly, or it is not. Questions are independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A student takes a multiple-choice test that has 11 questions.

This means that n = 11

Each question has five choices.

This means that p = \frac{1}{5} = 0.2

(a) Find P (6)

This is P(X = 6).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{11,6}.(0.2)^{6}.(0.8)^{5} = 0.0097

P(6) = 0.0097

(b) Find P (More than 3).

Either P is 3 or less, or it is more than three. The sum of the probabilities of these outcomes is 1. So

P(X \leq 3) + P(X > 3) = 1

We want P(X > 3). So

P(X > 3) = 1 - P(X \leq 3)

In which

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{11,0}.(0.2)^{0}.(0.8)^{11} = 0.0859

P(X = 1) = C_{11,1}.(0.2)^{1}.(0.8)^{10} = 0.2362

P(X = 2) = C_{11,2}.(0.2)^{2}.(0.8)^{9} = 0.2953

P(X = 3) = C_{11,3}.(0.2)^{3}.(0.8)^{8} = 0.2215

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0859 + 0.2362 + 0.2953 + 0.2215 = 0.8389

Then

P(X > 3) = 1 - P(X \leq 3) = 1 - 0.8389 = 0.1611

P(More than 3) = 0.1611

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4 years ago
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The answer is 2.8in

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Use the image provided to answer please​
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B? I’m not quite sure but I think it’s that.
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