Question

Write an equation for a line that is perpendicular to the line 6y – 9x = 12

Answer 1

Answer:

y = -2/3x + 4

Step-by-step explanation:

first we take the original equation and convert it to y=mx+b (a form we know how to graph)

that gives us y = 3/2x + 2

(Here's my work for that):

6y - 9x = 12; add 9x on both sides

6y = 9x + 12; divide 6 on both sides

y = 9/6x + 12/6

y = 3/2x + 2

next to make a line *perpendicular* to this, we make the slope negative and swap the fraction (-2/3)

then we just uh graph that slope and try to find the y intercept. i did it already and i got 4

Answer 2

Answer:

Step-by-step explanation:

You need one more piece of information to get a specific line. I'll get the general one and then we'll see what comes of it.

Add 9x to both sides.

6y - 9x + 9x = 9x + 12

6y = 9x + 12                   Divide by 6

6y/6 = 9x/6 + 12/6

y = 1.5x + 2

Now the perpendicular line must have a slope that is found by using

m1 * m2 = - 1

m1 = 1.5             From the equation above.

1.5 * m2 = - 1     Divide by 1.5

m2 = -1/1.5

m2 = - 2/3

So far what you have is

y = -2/3 x + b                  You need a value for b. Usually that is found with a point. But I will just call b = 1 since there is nothing else to do

The complete equation becomes

y = -2/3 x + 1

The graph is enclosed.