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bazaltina [42]
2 years ago
7

When a mixture of iron powder and sulphur is heated it glows more brightly than that of iron filings and sulphur.Explain this ob

servation
Chemistry
1 answer:
Bond [772]2 years ago
3 0

Answer:

I don't know

Explanation:

mixture of iron powder and sulphur heated it glows because sulphur and iron are more reactive metals that they shine and sulphur can react with water produce fire it's write

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...............………...mkmlkml;m
bagirrra123 [75]

Answer:

390

Explanation:

Specific heat capacity= heat/mass × temperature

x = 2925 \div 0.5 \times 15 = 390

Remember you convert gram into kilogram and 1 gram =0.001 kilogram

5 0
3 years ago
2. When vinegar is added to eggshells, carbon dioxide gas is produced.​Why?
skad [1K]

Answer:

same as his

Explanation:

4 0
2 years ago
Which substance is important in making plastics?
QveST [7]
Based on the compounds given, I can say that the substance that is considered essential in the plastic making is NITRIC ACID. This substance is also known as aqua fortis and spirit of niter wherein this decomposes into oxides of nitrogen and water. The answer would be the last option. Hope this helps.
8 0
3 years ago
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What is 24.29 g + 4.336 g - 17.900 g
choli [55]

Answer:

10.726g

Explanation:

5 0
2 years ago
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Convert the following into balanced equations. ( Use the lowest possible coefficents)?(a) When gallium metal is heated in oxygen
ehidna [41]

Answer:

Explanation:

(a) Balanced reaction of gallium with oxygen is as follows:

4Ga(s)+3O_2(g) \rightarrow 2Ga_2O_3 (s)

(b) C_6H_{14}(l)+O_2(g)\rightarrow CO_2(g)+H_2O(l)

Multiply the carbon dioxide by 6 to balance carbon as follows:

C_6H_{14}(l)+O_2(g)\rightarrow 6CO_2(g)+H_2O(l)

After that multiply H2O by 7 to balance hydrogen as follows:

C_6H_{14}(l)+O_2(g)\rightarrow CO_2(g)+7H_2O(l)

Finally balance oxygen by multiplying O2 by 19/2. Therefore, balanced reaction is as follows:

C_6H_{14}(l)+\frac{19}{2} O_2(g)\rightarrow 6CO_2(g)+7H_2O(l)

(c) Na_3PO_4(s)+CaCl_2 \rightarrow Ca_3(PO_4)_2+NaCl

first balance calcium, by multiply CaCl_2 by 3 as follows:

Na_3PO_4(s)+3CaCl_2 \rightarrow Ca_3(PO_4)_2+NaCl

After that balance phosphorous by multiplying Na_3PO_4 by 2 as follows:

2Na_3PO_4(s)+3CaCl_2 \rightarrow Ca_3(PO_4)_2+NaCl

Finally balance Na by multiplying NaCl by 6. Therefore, balance reaction is as follows:

2Na_3PO_4(s)+3CaCl_2 \rightarrow Ca_3(PO_4)_2+6NaCl

3 0
3 years ago
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