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3 years ago

Which particle in an atom is lost or gained to make an ion

Chemistry

1 answer:

denpristay [2]3 years ago

7 0

An electron because that is the only part able to be lost or gained without nuclear action needed

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The half-life of U234 is 25200 years. How much of a 100 gram sample remains after 352800 years?

lord [1]

The answer is um hold on need a dictionary lol jk but i will be right back to help you

6 0

4 years ago

if 26.8g of copper (ll) chloride are dissolved in sufficient water to make 4.00 L of solution, what is the molarity of the solut

artcher [175]

Answer: Molarity of the solution is $4.97 \times 10^{-2} M$ and water is the solvent.

Explanation:

Given: Mass of solute = 26.8 g

Volume = 4.00 L

Now, moles of copper (II) chloride (molar mass = 134.45 g/mol) are calculated as follows.

$No. of moles = \frac{mass}{molar mass}\\= \frac{26.8 g}{134.45 g/mol}\\= 0.199 mol$

Molarity is the number of moles of a substance divided by volume of solution in liter.

Therefore, molarity of given solution is calculated as follows.

$Molarity = \frac{no. of moles}{Volume (in L)}\\= \frac{0.199 mol}{4.00 L}\\= 0.04975 M\\= 4.97 \times 10^{-2} M$

Solvent is defined as a component which is present in higher amount in a solution. Generally, a solvent is present in liquid state but it can also be a solid or gas.

In the given solution, copper (II) chloride is dissolved in water so copper (II) chloride is the solute and water is the solvent.

Thus, we can conclude that molarity of the solution is $4.97 \times 10^{-2} M$ and water is the solvent.

4 0

4 years ago

It take 38.70cm³ of 1.90m NaoH to neutralize 10.30cm³ of H2so4 in a battery, calculate the molar concentration of H2so4

zlopas [31]

Answer:

$M_{acid}=3.57M$

Explanation:

Hello there!

In this case, since this acid-base neutralization is performed in a 1:2 mole ratio of acid to base as the former is a diprotic acid (two hydrogen ions in the molecule), we can write the following equation:

$2M_{acid}V_{acid}=M_{base}V_{base}$

In such a way, we can solve for the molarity of the acid, given the molarity and concentration of the NaOH base and the volume of the acid:

$M_{acid}=\frac{M_{base}V_{base}}{2V_{acid}}$

Thus, we plug in the given data to obtain:

$M_{acid}=\frac{38.70cm^3*1.90M}{2(10.30cm^3)} \\\\M_{acid}=3.57M$

Best regards!

8 0

3 years ago

What role do catalysts play in chemical reactions?

Ludmilka [50]

Role of a catalysts in chemical reactions:
Catalyst is a substance, usually used in small amounts relative to the reactants, that modifies and increases the rate of a reaction without being consumed in the process.

5 0

3 years ago

Plants absorb water in the soil through their roots and pump this water up to deliver

Dafna11 [192]

It is transpiration.

7 0

3 years ago