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inysia [295]
3 years ago
5

If this analysis is based on 15 data pairs, what is the 95% confidence interval for the slope of the regression line?

Mathematics
1 answer:
NemiM [27]3 years ago
8 0

Answer:

A. (-2.28, 3.38)

Step-by-step explanation:

The confidence interval of the slope :

b ± Tcritical*SE

Tcritical at 95%, df = n - 2 = (15 - 2) = 13

Tcritical = 2.160369

b = slope Coefficient = 0.54924

S.E = 1.311

Hence, we have :

Confidence interval = 0.54924 ± (2.160369 * 1.311)

Confidence interval = 0.54924 ± 2.832243759

Lower boundary = 0.54924 - 2.83224 = - 2.283

Upper boundary = 0.54924 + 2.83224 = 3.3814

The answer option is A. (-2.28, 3.38)

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A picture is 46 cm by 32 cm. A scale diagram of the picture must fit in a space that is 3 m by 2 m. Which scale would be the mos
Marrrta [24]

Answer:

A picture that is 46cm by 32 cm must fit in a space that is 3m by 2m

First, let's rewrite both of these dimensions in the same units.

Knowing that:

1m = 100cm

Then the dimensions of the space can be rewritten from:

3m by 2m

to:

300cm by 200cm

So, if we enlarge our original picture by a scale factor K, the new dimensions of the picture will be:

K*46cm by K*32cm

Now we just need to find a value of K such that:

K*46cm is something near to 300cm

K*32cm is something near to 200cm

First, we can solve the equation:

K*46cm = 300cm

solving this for K we get:

K = 300cm/46cm = 6.5

While if we solve the equation:

K*32cm = 200cm

we get:

K = 200cm/32cm = 6.25

So we got two possible scale factors.

Which one we should take?

Notice that if we wanted to use the larger one (K = 6.5) for the 32cm side. the new length would be:

32cm*6.5 = 208cm

This is larger than the 200cm of space that we have

Then we can not select the larger option, we can only take the other value:

K = 6.25

Then we can conclude that a reasonable scale factor to use is K = 6.25

4 0
3 years ago
The letter or number on each side indicates the side's measure and the letter or number in the interior of each angle of each tr
Travka [436]

Answer:

\beta , \alpha , \gamma

Step-by-step explanation:

6 0
3 years ago
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The relationship between two variables partialling out the effect that a third variable has on one of those variables can be exp
TiliK225 [7]

Answer: partial correlation.

Explanation:

partial correlation measures the degree of association between two random variables, with the effect of a set of controlling random variables removed. If we are interested in finding to what extent there is a numerical relationship between two variables of interest, using their correlation coefficient will give misleading results if there is another, confounding, variable that is numerically related to both variables of interest. This misleading information can be avoided by controlling for the confounding variable, which is done by computing the partial correlation coefficient.

3 0
3 years ago
A store is having a sale on jelly beans and trail mix. For 3 pounds of jelly beans and 5 pounds of trail mix, the total cost is
Maurinko [17]
Set up your two equations: 
<span>9x+7y=53 </span>
<span>3x+5y=25 </span>
<span>X=cost per pound of jelly bean </span>
<span>Y=cost per pound of trail mix </span>
<span>Multiply the second equation by (-3): </span>
<span>-9x-15y=-75 </span>
<span>+ 9x+7y=53 <---- copy first equation and add them </span>
<span>—————— </span>
<span>0x-8y=-22 </span>
<span>Then solve for y: </span>
<span>Y=2.76 this is your cost per pound of trail mix. </span>
<span>Then plug y back in to one of the original equations and solve for x: </span>
<span>3x+7(2.75)=25 </span>
<span>X=3.75 this is you cost per pound of jelly beans</span>
6 0
3 years ago
Line 1 passes through the points (-4, -6) and (12,2). line 2 passes through the points (-6,-2) and (-2,0). Do the lines intersec
kifflom [539]

The lines dont intersect

7 0
3 years ago
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