Answer:
A. (-2.28, 3.38)
Step-by-step explanation:
The confidence interval of the slope :
b ± Tcritical*SE
Tcritical at 95%, df = n - 2 = (15 - 2) = 13
Tcritical = 2.160369
b = slope Coefficient = 0.54924
S.E = 1.311
Hence, we have :
Confidence interval = 0.54924 ± (2.160369 * 1.311)
Confidence interval = 0.54924 ± 2.832243759
Lower boundary = 0.54924 - 2.83224 = - 2.283
Upper boundary = 0.54924 + 2.83224 = 3.3814
The answer option is A. (-2.28, 3.38)
Answer:
if ∠Q=∠R
draw an angular bisector from P to QR in which it intersect wit Qr at point S
now we have two triangle : QPS and RSP
in which angle : QPS=RPS ( PS is angular bisector)
and we have angle Q and angle R are equal
and PS is common side
this makes triangle QPS and RSP are congruent by AAS(angle angle side)
which also means that pQ=PR ( proved)
