How many cylinder containers that are the same height and have the same base area would these three henna cones fill up?

Could you please solve this I need this for today... pls

Greeley [361]

Hi,

$3 \frac{2}{3} x - \frac{4}{5} (x - 3 \frac{3}{4} )$

$2x - \frac{4}{5} x + \frac{9}{5}$

$\frac{6}{5}x + \frac{9}{5}$

success:)

4 0

3 years ago

The chance of women getting breast cancer is 1 out of 8. at this rate how many women in a classroom of 32 women would be expecte

stepladder [879]

The general probability is 1/8. For it to be applicable to 32 women, one must multiply 4 to the numerator and denominator.

The final probability would be (1x4)/(8x4) which is 4/32.

Therefore, 4 women would be the answer.

7 0

3 years ago

The graph shows the relationship between the total cost and the number of gift cards that Raj bought for raffle prizes.

BabaBlast [244]

The problem is as following:

The graph shows the relationship between the total cost and the number of gift cards that Raj bought for raffle prizes. What would be the cost for 5 of the gift cards? $80, $90, $100 Or $110

===============================================================

Solution:

The points of the figure represents a straight line

The general form of the straight line is ⇒ y = mx + c

where m is the slope and c is constant

let x ⇒ The number of gifts cards , y ⇒ Total cost (in $)

we will find m and c using the points (1,20) , (2,40)

The slope = m = $\frac{y_{2} - y_{1}}{x_{2}-x_{1}} =\frac{40-20}{2-1} =\frac{20}{1}=20$

∴ y = 20x + c

Substitute with the point (1,20) ⇒ y = 20 at x = 1

∴ 20 = 20 * 1 + c

∴ 20 = 20 + c

∴ c = 0

∴ The equation of the line ⇒⇒⇒ y = 20x

To find the cost for 5 of the gift cards substitute with x = 5

∴ y = 20 * 5 = 100

So, the cost for 5 of the gift cards = $100

The correct answer is option 3 ⇒⇒⇒ $100

6 0

3 years ago

Read 2 more answers

First-order linear differential equations

kkurt [141]

Answer:

$(1)\ logy\ =\ -sint\ +\ c$

$(2)\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

Step-by-step explanation:

1. Given differential equation is

$\dfrac{dy}{dt}+ycost = 0$

$=>\ \dfrac{dy}{dt}\ =\ -ycost$

$=>\ \dfrac{dy}{y}\ =\ -cost dt$

On integrating both sides, we will have

$\int{\dfrac{dy}{y}}\ =\ \int{-cost\ dt}$

$=>\ logy\ =\ -sint\ +\ c$

Hence, the solution of given differential equation can be given by

$logy\ =\ -sint\ +\ c.$

2. Given differential equation,

$\dfrac{dy}{dt}\ -\ 2ty\ =\ t$

$=>\ \dfrac{dy}{dt}\ =\ t\ +\ 2ty$

$=>\ \dfrac{dy}{dt}\ =\ 2t(y+\dfrac{1}{2})$

$=>\ \dfrac{dy}{(y+\dfrac{1}{2})}\ =\ 2t dt$

On integrating both sides, we will have

$\int{\dfrac{dy}{(y+\dfrac{1}{2})}}\ =\ \int{2t dt}$

$=>\ log(y+\dfrac{1}{2})\ =\ 2.\dfrac{t^2}{2}\ + c$

$=>\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

Hence, the solution of given differential equation is

$log(y+\dfrac{1}{2})\ =\ t^2\ +\ c$

8 0

4 years ago

A coin is tossed 20 times. It lands on heads 9 times. What is the P(H) according to your experiment? Write your answer as a frac

Mama L [17]

Answer:

$\frac{9}{20}=0.45=45$ %

Step-by-step explanation:

Probability is found by first forming a fraction where the numerator represents the number of desired outcomes and the denominator represents the total number of outcomes. In this case, the desired outcomes is the amount of times the coin lands on heads (9) and the total outcomes is the number of times the coin is tossed (20):

$\frac{9}{20}$

Divide numerator by denominator to get a decimal: 9÷20= 0.45

Multiply the decimal by 100 to get a percent: 0.45 x 100 = 45%

8 0

3 years ago