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Ugo [173]
3 years ago
5

Define global variables called highestNum, userInput and sumOfNums and initialize them. In Main call 2 methods: 1) UserData() 2)

DisplayResults()
Task #1:In the UserData() method ask the user to give you a number between 9 and 20, exclusive. Validate this input Then, create a loop that will loop THAT amount of times. Inside that loop generate a random number between 1-100. In that loop check each generated number in order to find the highest number generated. Accumulate all numbers to sumOfNums
Task #2: In the displayResults() method print the following: "There were x numbers generated" "the highest number generated is x" "The sum of the numbers is x" "The average of these numbers is x"
Computers and Technology
1 answer:
Montano1993 [528]3 years ago
5 0

Answer:

Explanation:

The following code is written in Java. It creates the two methods as requested using the Scanner and Random built-in classes in Java. Once the loop is completed and the highestNum is calculated, then the displayResults method is called to print out all the information in the correct format. The output of the program can be seen in the attached image below.

import java.util.Random;

import java.util.Scanner;

class Brainly {

   static int highestNum = 0;

   static int userInput;

   static int sumOfNums = 0;

   public static void main(String[] args) {

       userData();

       displayResults();

   }

   private static void userData() {

       Scanner in = new Scanner(System.in);

       Random rand = new Random();

       System.out.println("Enter a number between 9 and 20: ");

       userInput = in.nextInt();

       if ((userInput >= 9) && (userInput <= 20)) {

           for (int i = 0; i < userInput; i++) {

               int num = rand.nextInt(100);

               if (num > highestNum) {

                   highestNum = num;

               }

               sumOfNums += num;

           }

       }

   }

   public static void displayResults() {

       System.out.println("There were " + userInput + " numbers generated");

       System.out.println("The highest number generated is " + highestNum);

       System.out.println("The sum of the numbers is " + sumOfNums);

       int average = sumOfNums / userInput;

       System.out.println("The average of the numbers is " + average);

   }

}

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Explanation:

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Modify the list according to the following: append the smallest value at the end of the list when all numbers in the list are ne
ddd [48]

Answer:

The solution code is written in Python 3:

  1. def modifyList(listNumber):
  2.    posCount = 0
  3.    negCount = 0
  4.    for x in listNumber:
  5.        if x > 0:
  6.            posCount += 1
  7.        else:
  8.            negCount += 1
  9.    
  10.    if(posCount == len(listNumber)):
  11.        listNumber.append(max(listNumber))
  12.    
  13.    if(negCount == len(listNumber)):
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  18. modifyList([1,99,8])
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Explanation:

The key step to solve this problem is to define two variables, posCount and negCount, to track the number of positive value and negative value from the input list (Line 2 - 3).

To track the posCount and negCount, we can traverse through the for-loop and create if else statement to check if the current number x is bigger than 0 then increment posCount by 1 otherwise increment negCount (Line 5- 9).

If all number in the list are positive, the posCount should be equal to the length of the input list and the same rule is applied to negCount. If one of them happens, the listNumber will append either the maximum number (Line 11 -12) or append the minimum number (Line 14-15).

If both posCount and negCount are not equal to the list length, the block of code Line 11 -15 will be skipped.

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Therefore, if you want to set the sticky bit on an existing directory, subdir, without otherwise altering its permissions. to do so, you should type chmod a <u>t  <subdir>.</u>

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