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natta225 [31]
3 years ago
14

Easy 20 points please tell me if I got it right and if not please tell me the right answer

Mathematics
1 answer:
mash [69]3 years ago
3 0

Answer:

No, you are not correct.

It should look like this:

                              Prefer colorful decorations      Prefer neutral decorations

Pay attention                           20                                                  25

to fashion

Do not pay

attention to                              72                                                      33

fashion

Step-by-step explanation:

33 is 22% of 150. In the question it states that 70% of people do not pay attention to fashion. We need to find the other 48% here. In order to do that we multiply .48 by 150. That gets us 72. To check that answer you can add both 72 and 33 and then divide by 150, which gets 70%.

To get the amount of people that prefer neutral decorations and pay attention to fashion we need to add up 20 + 72 + 33 and that equals 125. Next, we take 150 and minus 125 of it to get 25.

<em>Hope this helps!!</em>

<em>- Kay :)</em>

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Solve using quadratic formula for 2x^(2)-10x+5=0
sergij07 [2.7K]

Answer:

x=\frac{5+\sqrt{15}}{2},\:x=\frac{5-\sqrt{15}}{2}

Step-by-step explanation:

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=2,\:b=-10,\:c=5

x_{1,\:2}=\frac{-\left(-10\right)\pm \sqrt{\left(-10\right)^2-4\cdot \:2\cdot \:5}}{2\cdot \:2}

\sqrt{\left(-10\right)^2-4\cdot \:2\cdot \:5}

Apply exponent rule: (-a)^n=a^n, if n is even

\left(-10\right)^2=10^2

=\sqrt{10^2-4\cdot \:2\cdot \:5}

\mathrm{Multiply\:the\:numbers:}\:4\cdot \:2\cdot \:5=40

=\sqrt{10^2-40}

10^2=100

=\sqrt{100-40}

\mathrm{Subtract\:the\:numbers:}\:100-40=60

=\sqrt{60}

60\:\mathrm{divides\:by}\:2\quad \:60=30\cdot \:2

=2\cdot \:30

30\:\mathrm{divides\:by}\:2\quad \:30=15\cdot \:2

=2\cdot \:2\cdot \:15

15\:\mathrm{divides\:by}\:3\quad \:15=5\cdot \:3

=2\cdot \:2\cdot \:3\cdot \:5

2,\:3,\:5\mathrm{\:are\:all\:prime\:numbers,\:therefore\:no\:further\:factorization\:is\:possible}

=2\cdot \:2\cdot \:3\cdot \:5

=2^2\cdot \:3\cdot \:5

=\sqrt{2^2\cdot \:3\cdot \:5}

Apply Radical Rule:

=\sqrt{2^2}\sqrt{3\cdot \:5}

Apply Radical Rule:

\sqrt{2^2}=2

=2\sqrt{3\cdot \:5}

\mathrm{Refine}

=2\sqrt{15}

x_{1,\:2}=\frac{-\left(-10\right)\pm \:2\sqrt{15}}{2\cdot \:2}

\mathrm{Separate\:the\:solutions}

x_1=\frac{-\left(-10\right)+2\sqrt{15}}{2\cdot \:2},\:x_2=\frac{-\left(-10\right)-2\sqrt{15}}{2\cdot \:2}

\frac{-\left(-10\right)+2\sqrt{15}}{2\cdot \:2}

Apply Rule -(-a)=a

=\frac{10+2\sqrt{15}}{2\cdot \:2}

\mathrm{Multiply\:the\:numbers:}\:2\cdot \:2=4

=\frac{10+2\sqrt{15}}{4}

=\frac{2\left(5+\sqrt{15}\right)}{4}

\mathrm{Cancel\:the\:common\:factor:}\:2

=\frac{5+\sqrt{15}}{2}

\frac{-\left(-10\right)-2\sqrt{15}}{2\cdot \:2}

=\frac{10-2\sqrt{15}}{2\cdot \:2}

\mathrm{Multiply\:the\:numbers:}\:2\cdot \:2=4

=\frac{10-2\sqrt{15}}{4}

=\frac{2\left(5-\sqrt{15}\right)}{4}

\mathrm{Cancel\:the\:common\:factor:}\:2

=\frac{5-\sqrt{15}}{2}

\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

x=\frac{5+\sqrt{15}}{2},\:x=\frac{5-\sqrt{15}}{2}

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Answer: ....

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1 year ago
A chemist needs a 70% solution of tannic acid. How much distilled water must he add to 5 gallons of a 90% solution of acid to ob
kolezko [41]
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1 = 0.7x
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6 0
3 years ago
Ignore the answer I put please help and I’ll give brainliest
Leokris [45]

Answer:

B.

Step-by-step explanation:

3/12 reduces to 1/4.

1/2 alone is greater than 1/4, so when 2/10 is added to 1/2, it is certainly greater than 3/12.

Answer: B.

5 0
3 years ago
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