The correct answer is choice d.....
“C” Os the correct answer
You just have to add one eqaution to another :
-x + x -y + 2y = 7 + 7
y = 14
Then apply y = 14 to one of the equations :
eg: x + 2(14) = 7
x + 28 = 7
x = - 21
The awnser is x= -21 y= 14
I hope i awnsered your question
Answer:
Step-by-step explanation:
Alright, lets get started.
Suppose the first fraction is : 
Suppose the second fraction is : 
The sum of both fraction is given as : 
.......................equation (1)
The difference of both fraction is given as : 
.........................equation (2)
Adding equation (1) and equation (2)
making common denominator
Hence,
Plugging the value of in equation (1)
Subtracting 
in both sides
Hence both fractions are 
...................Answer
Hope it will help :)
Answer:
RTA= (x-2)·(x-11/2)/(x-2)(x-4)= (you can simplify again if you want by eliminating both (x-2)
(x-11/2)/(x-4)
Step-by-step explanation:
Ok we need to simplify the expression so:
x^2+3x-10= Bhaskara formula=
-3(±√9-4·1·(-10))/2·1=
X1=(-3+7/2)--> X1=2(R)---> (X-R)--->X-2
X2=(-3-7)/2 --> X2=11/2(R)---> (X-R)--->X-11/2
x^2-6x+8= Bhaskara formula=
6(±√36-4·1·8)/2·1=
X1=(6-2)/2=2--> X1=2(R)---> (X-R)--->X-2
X2=(6+2)/2=2--> X2=4(R)---> (X-R)--->X-4
so, The simplify expression is
(x-2)·(x-11/2)/(x-2)(x-4)=
