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baherus [9]
3 years ago
9

Jack wants to abopt all kittens that weigh more than 4 ounces how many kittens will he abopt

Mathematics
1 answer:
lbvjy [14]3 years ago
5 0
Yea he will
Adopt that many kittens
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Which coordinates , are shared by The Triangle and the rectangle
tigry1 [53]
(5,3) are shared by both
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3 years ago
Does anyone know this?
Sati [7]

Answer:

Step-by-step explanation:

-10<x≤8

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3 years ago
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Help me solve this image please!!!
tresset_1 [31]

Based on the information, Christian would have $5525.5 of an annuity.

<h3>How to calculate the annuity?</h3>

According to the given information, the number of coffees per week is 3 then, per month is 3x4 = 12

Each coffee is $4.5. Then monthly expenditure for coffees is 12 x 4.5 = $54

Rate of interest r = 1.6% = 1.6/100 = 0.016 and for monthly compounding r = 0.016/12 = 0.00133

n = number of payments = 8 x 12 = 96

We can use the formula for finding the future value as below

FV = C x [ ( 1 + r )n-1 ] / ( r )

FV = 54 x [ ( 1 + 0.00133 )96 – 1 ] / (0.00133)

= 54 x [ (1.13609 - 1)] / (0.00133)

= 54 x 0.13609 / (0.00133)

= 54 x 102.3233

= 5525.5

Therefore Christian would have $5525.5 of the annuity.

Learn more about annuity on:

brainly.com/question/5303391

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5 0
2 years ago
Please help. I’ll mark you as brainliest if correct!
erica [24]

Step-by-step explanation:

Nicole starts with the budget:

$395

Now, she only expects to pay half the deposit;

$72 ÷ 2 = $36

Subtract this from the budget:

$395 - $36 = $359

Divide by cost per hour:

$359 ÷ $60 = 5.983333... (3 repeating)

This means, Nicole can rent a <em>maximum</em><em> </em>of 5 hours with her budget. The inequality would be

x  \leqslant 5

5 0
3 years ago
What is the confidence interval estimate of the population mean percentage change in the price per share of stock during the fir
I am Lyosha [343]

Answer:

(-0.1059 ; - 0.0337)

Step-by-step explanation:

The data table is attached in the picture below:

These is a matched pair design ; which requires taking the difference of the two values for each sample :

The mean and standard deviation of the difference will be used to construct the confidence interval :

The mean of difference, dbar = Σx/n = - 0.0698

The standard deviation of difference, Sd ;

Sd = [√Σ(d - dbar)²/(n-1)] = 0.1054

n = sample size = 25

The confidence interval :

dbar ± [TCritical * Sd/√n]

Tcritical at 90% ; df = n -1 = 25 -1

Tcritical(90% , 24) = 1.1711

C.I = - 0.0698 ± (1.711 * 0.1054/√25)

C.I = - 0.0698 ± 0.0361

C.I = (-0.1059 ; - 0.0337)

5 0
2 years ago
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