Answer:
The quotient of 4 and 9 raised to the power of r.
Step-by-step explanation:
Answer:
x= 1 , y=4
Step-by-step explanation:
x-y= -3 => Equation 1
x+5y= 21 => Equation 2
<u>Substitut</u><u>ion</u><u> </u><u>Method</u><u>:</u>
<u>Substitu</u><u>te</u><u> </u><u>Equation</u><u> </u><u>1</u>=>
x=y-3 <= Equation 3
Put x=y-3 in Equation 2:
x+5y=21
( y-3)+5y=21
y-3+5y=21
6y-3=21
6y=21+3
6y=24
y=24÷6
y=4
Put y=4 in Equation 1:
x-y= -3
x-4=-3
x=4-3
x=1
Hope this helps :)
Answer:
63 Jelly Beans
Step-by-step explanation:
The unknown is the number of jelly beans originally in the bag or x
First he had x jelly beans
The he ate one-third of them
He then ate 16 more jelly beans
This was equal to 37 jelly beans
This is the equation
Now solve for x
Subtract 16 from both sides
Multiply both sides by 3
63 Jelly Beans
Answer:
E(w) = 1600000
v(w) = 240000
Step-by-step explanation:
given data
sequence = 1 million iid (+1 and +2)
probability of transmitting a +1 = 0.4
solution
sequence will be here as
P{Xi = k } = 0.4 for k = +1
0.6 for k = +2
and define is
x1 + x2 + ................ + X1000000
so for expected value for W
E(w) = E( x1 + x2 + ................ + X1000000 ) ......................1
as per the linear probability of expectation
E(w) = 1000000 ( 0.4 × 1 + 0.6 × 2)
E(w) = 1600000
and
for variance of W
v(w) = V ( x1 + x2 + ................ + X1000000 ) ..........................2
v(w) = V x1 + V x2 + ................ + V X1000000
here also same as that xi are i.e d so cov(xi, xj ) = 0 and i ≠ j
so
v(w) = 1000000 ( v(x) )
v(w) = 1000000 ( 0.24)
v(w) = 240000
X^2+x-30 -- find two numbers that add to one and multiply to -30, which would be 6 and -5. so now you have x^2+6x-5x-30. factor out x and 5 to get x(x+6)-5(x+6). so you get (x+6)*(x-5)
