Y^3 + 5y^2 - 14y
first factor out a "y"
y(y^2 + 5y - 14)
y(y + 7)(y - 2)
The dimensions are then;
y
y + 7
y - 2
I think it means you have to find the area of both shapes and then compare them to see if Liam is correct if he is not correct say why. Hope this helps :)
Answer:
Length (in) Width (in)
2 5
4 10
6 15
8 20
Step-by-step explanation:
Answer: $0.12 per pen
Step-by-step explanation: 1.44 divided by 12
There are 3 units between y int. One is at y=0 and the other is y=-3