Question

1) Find the measure of 0. (imagine that is an x) 2) Then, find the measure of AB. (the length from A to B) ​

Answer 1

Answer:

θ ≈ 50°, AB ≈ 15.6

Step-by-step explanation:

Using the tangent ratio in the right triangle

tanθ = $\frac{opposite}{adjacent}$ = $\frac{BC}{AC}$ = $\frac{11.9}{10}$ = 1.19 , then

θ = $tan^{-1}$ (1.19 ) ≈ 50° ( to the nearest degree

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Using the cosine ratio in the right triangle

cos50° = $\frac{adjacent}{hypotenuse}$ = $\frac{AC}{AB}$ = $\frac{10}{AB}$ ( multiply both sides by AB )

AB × cos50° = 10 ( divide both sides by cos50° )

AB = $\frac{10}{cos50}$ ≈ 15.6 ( to 1 dec. place )