Question

​​ALGUIEN POR FAVOR AYUDEME A RESOLVER ESTOS 3 PROBLEMAS

Answer 1

Answer:

a. x^2 - 1

b. x^2 - 6x + 9

c. $\dfrac{3x + 1}{x^2 + x}$

Step-by-step explanation:

a.

(x + 1)(x - 1) =

= x^2 - x + x - 1

= x^2 - 1

b.

(x - 3)^2 =

= (x - 3)(x - 3)

= x^2 - 3x - 3x + 9

= x^2 - 6x + 9

c.

$\dfrac{3 + \frac{1}{x}}{1 + x} =$

$= \dfrac{x(3 + \frac{1}{x})}{x(1 + x)}$

$= \dfrac{3x + 1}{x + x^2}$

$= \dfrac{3x + 1}{x^2 + x}$