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Natasha2012 [34]
3 years ago
5

Find the area of the triangle. Round your answer to the nearest tenth.

Mathematics
1 answer:
34kurt3 years ago
3 0

Answer:

A

Step-by-step explanation:

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Write the equation in standard form<br><br> y = -10x + 6
Mumz [18]
Step (1) Flip the equation

−10x+6=y


Step (2) Add -6 to both sides

−10x+6+−6=y+−6

−10x=y−6

Step (3) Divide both sides by -10

−10x−10=y−6−10

ANSWER
x =  \frac{ - 1}{10} y +  \frac{3}{5}
5 0
3 years ago
Im going to give 15 points for this question please answer it
Gnom [1K]
I know, you have to divide 90 by what ever the length is, then you have to figure out where the points are. So it should be.... D!!!
8 0
4 years ago
Find the exact value, without a
Ghella [55]

Answer:

√(2 + √3)/4

Step-by-step explanation:

Sine 5π/12 = Sine (5π/6)/2

Recall

π = 180°

Thus,

Sine (5π/6)/2 = Sine (5×180 /6)/2

= Sine 150/2

Recall

Sine θ/2 = √(1 – Cos θ)/2

Thus,

Sine 150/2 = √(1 – Cos 150)/2

But, Cosine is negative in the 2nd quadrant. Thus,

Cos 150 = – Cos 30 = –√3/2

Thus,

√(1 – Cos 150)/2 = √(1 – –√3/2 )/2

= √(1 + √3/2 )/2

= √[(2 + √3)/2 ÷ 2]

= √[(2 + √3)/2 × 1/2]

= √(2 + √3)/4

Therefore,

Sine 5π/12 = √(2 + √3)/4

4 0
3 years ago
9sin(2x) sin (x) = 9cos(x)
nikdorinn [45]

Answer:

\sin(2x)  = 2 \sin(x)  \cos(x)  \\ 9( 2 \sin(x)  \cos(x) ) \sin(x)  = 9 \cos(x)  \\ 18 { \sin}^{2} (x)9 \cos(x)  - 9 \cos(x)  = 0 \\ 9 \cos(x) (2{ \sin}^{2} (x) - 1) = 0 \\ 9 \cos(x) = 0 \: or \: 2{ \sin}^{2} (x) - 1 = 0 \\  \sin(x)  =  \pm \frac{1}{ \sqrt{2} }  \\  \cos(x)  = 0 \\ x =  { \cos}^{ - 1} (0) \\ x =  \frac{ \pi}{2}  = 90 \degree \\ x = \frac{ \pi}{2} + 2\pi \: n \:  \forall \: n \:  \in \:  \Z  \\ = 90 \degree +  360\degree\: n \:  \forall \: n \:  \in \:  \Z \\  =  \pm\frac{ \pi}{4}  \pm2\pi \: n \:  \forall \: n \:  \in \:  \Z \\ x =  \pm45\degree  \pm 360\degree\: n \:  \forall \: n \:  \in \:  \Z

8 0
2 years ago
2800 ml +2.6 L<br> 2800 ml +2.6 L
Tom [10]

Answer:

10 800 ml

Step-by-step explanation:

I hope this helps :}

5 0
3 years ago
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