It would 6 Pounds/ Liquid gallon.
Answer:
a. p = the population proportion of UF students who would support making the Tuesday before Thanksgiving break a holiday.
Step-by-step explanation:
For each student, there are only two possible outcomes. Either they are in favor of making the Tuesday before Thanksgiving a holiday, or they are against. This means that we can solve this problem using concepts of the binomial probability distribution.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinatios of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
So, the binomial probability distribution has two parameters, n and p.
In this problem, we have that
and
. So the parameter is
a. p = the population proportion of UF students who would support making the Tuesday before Thanksgiving break a holiday.
Answer:
-25
Step-by-step explanation:
10^2 ÷ -2^2 = -25
That's why the answer is -25.
Probablity=desiredoutcomes/totalpossibleoutcomes
total possible outcomes=1+2+4+3=10
desired outcomes=4 blue
probablity=4/10=2/5=40%
Hey there!
Andrea makes 20% more than Cassidy.
Work:
10 x 0.20 = 2
10 - 2 = 8
So that proves it is 20%.
Hope this helps!