Question

A boy throws a baseball across a field. The ball reaches its maximum height, 18 meters, after 1 second. After approximately 2.3 seconds, the ball lands on the ground. The ball’s motion can be modeled using the function f(x) = –10x2 + 20x + 8. What is the height of the ball 1.5 seconds after it is thrown?

Answer 1

That would be 
 -10(1.5)^2 + 20(1.5) + 8  =   15.5 meters

Answer 2

Answer:

Step-by-step explanation:

Alright, lets get started.

The function that models the height of the ball is given by :

$f(x)=-10x^2+20x+8$

When we plug x as 1.5 , we could get the height f(1.5) as :

$f(1.5)=-10(1.5)^2 +20*1.5 +8$

$f(1.5)=-22.5+30+8$

$f(1.5)=15.5$

So the height of the ball after 1.5 second is 15.5 meters.   : Answer

Hope it will help :)