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patriot [66]
3 years ago
10

Select all the Intervals where f is increasing A) -3 B) -1 C) 3.5 D) None of the above

Mathematics
1 answer:
iVinArrow [24]3 years ago
8 0

Answer:

-3<x<-2

And

3.5<x<4.5

Step-by-step explanation:

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The product of a number and -3, increased by 8, is 20​
Pavlova-9 [17]

Answer:

The number is -4

Step-by-step explanation:

This is a simple equation. To set this up, you will have to multiply the number (n) by -3 and then add 8 to it before setting it all equal to 20.

-3n+8=20

-3n=12

n=-4

3 0
3 years ago
Given that 3(x-c)=2x+5 where c is an integer, shoe that x cannot be a multiple of 6
olga nikolaevna [1]

Answer:

The explanation in the procedure

Step-by-step explanation:

we have

3(x-c)=2x+5

solve for c

3x-3c=2x+5

3c=3x-2x-5

3c=x-5

c=(x-5)/3

For x=6 -----> Find the value of c

c=(6-5)/3=1/3 ------> is not an integer

therefore

x cannot be a multiple of 6

7 0
3 years ago
Find the area of this figure (sides meet at right angles)
Marrrta [24]

Answer:

60 cm²

Step-by-step explanation:

Just divide the figure in parts and then find their areas separately. At last, find the area of the whole figure by adding the areas of the parts

6 0
3 years ago
The circumference of a circle is 25.12 yards. What is the circle's diameter?
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8 0
4 years ago
Explain why f(x)=1/(x-3)^3 is not continuous at x=3
Bingel [31]
F(x)=1/(x-3)^3

The denominator can't be equal to zero (we can't divide by zero), then:
(x-3)^3 different 0
cubic root both sides:
cubic root [ (x-3)^3 ] different cubic root (0)
x-3 different 0
Adding 3 both sides:
x-3+3 different 0+3
x different 3

Then the function f is not defined at x=3

Answer: Option <span>b) f is not defined at x= 3</span>
3 0
3 years ago
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