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2 years ago

Select all the Intervals where f is increasing A) -3 B) -1 C) 3.5 D) None of the above

Mathematics

1 answer:

iVinArrow [24]2 years ago

8 0

Answer:

-3<x<-2

And

3.5<x<4.5

Step-by-step explanation:

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Find the measure of angle A

Ray Of Light [21]

In the fist you have to know: any angle opposite the head is equal in measurement.
so now we know one angle in the triangle it is 82
All corners of the triangle are equal 180
so we have to do this 180-82=98
so we have to collection (4x+8)+(8x-6)=98
12x+2=98
12x=96
x=8
4(8)+8=40
the answer is 40

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2 years ago

Suppose a triangle has sides a,b, and c, and that a^2+b^2>c^2. Let theta be the measure of the angle opposite the side of len

xenn [34]

B
b
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2 years ago

Read 2 more answers

Two problems here I need solved! I need every step, so please have that with your answers!!

Free_Kalibri [48]

QUESTION 1

We want to solve,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-6x+8}$

We factor the denominator of the fraction on the right hand side to get,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-4x - 2x+8}.$

This implies
$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x(x-4) - 2(x - 4)}.$

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{(x-4)(x - 2)}$

We multiply through by LCM of
$(x-4)(x - 2)$

$(x - 2) + x(x-4) = 2$

We expand to get,

$x - 2 + {x}^{2} - 4x= 2$

We group like terms and equate everything to zero,

${x}^{2} + x - 4x - 2 - 2 = 0$

We split the middle term,

${x}^{2} + - 3x - 4 = 0$

We factor to get,

${x}^{2} + x - 4x- 4 = 0$

$x(x + 1) - 4(x + 1) = 0$

$(x + 1)(x - 4) = 0$

$x + 1 = 0 \: or \: x - 4 = 0$

$x = - 1 \: or \: x = 4$

But
$x = 4$
is not in the domain of the given equation.

It is an extraneous solution.

$\therefore \: x = - 1$
is the only solution.

QUESTION 2

$\sqrt{x+11} -x=-1$

We add x to both sides,

$\sqrt{x+11} =x-1$

We square both sides,

$x + 11 = (x - 1)^{2}$

We expand to get,

$x + 11 = {x}^{2} - 2x + 1$

This implies,

${x}^{2} - 3x - 10 = 0$

We solve this quadratic equation by factorization,

${x}^{2} - 5x + 2x - 10 = 0$

$x(x - 5) + 2(x - 5) = 0$

$(x + 2)(x - 5) = 0$

$x + 2 = 0 \: or \: x - 5 = 0$

$x = - 2 \: or \: x = 5$

But
$x = - 2$
is an extraneous solution

$\therefore \: x = 5$

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3 years ago

Insect Weights Consider a dataset giving the adult weight of species of insects. Most species of insects weigh less than 5 grams

Ann [662]

Answer:

Step-by-step explanation:

71 grams would definitely be an outlier on the high side, whereas "most" species would weigh much less. Thus, the graph of this distribution of weights would be skewed towards the lower side, that is, to the left.

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3 years ago

Are 3k3 and 8k like terms?

givi [52]

Answer:

i believe so, 3k3 is just 3k to the third power so i think theyd be like terms still

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2 years ago