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Elenna [48]
2 years ago
13

What is the volume of the right cylinder?

Mathematics
1 answer:
Vesnalui [34]2 years ago
7 0
The answer would be C hope this helps;)
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Can you please help me with this problem!!
Black_prince [1.1K]

Answer:

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Step-by-step explanation:

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3x+2y-z=8<br> -3x+4y+5z=-14<br> X-3y+4z=-14
Luda [366]

Answer:

B? I think

Step-by-step explanation:

sorry I really want to help but I dont get what the question is asking

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3 years ago
Please anybody can help me anyone i need your help to solve this question​
podryga [215]

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Answer: 21p^2 + 3qp

Explanation:

To find the area of the triangle you have to do LxHx1/2

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3 years ago
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Answer:

Step-by-step explanation:

43.00 = 100% = 1

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3 years ago
Integrate e^x(sin(x) cos(x))
Karo-lina-s [1.5K]
I=\int e^x(\sin(x)\cos(x))dx=\int e^x(\frac{1}{2}\sin(2x))dx=\frac{1}{2}\int e^x\sin(2x)dx

\text{If }u=\sin(2x)\to du=2\cos(2x)dx~\text{and}~dv=e^xdx\to v=e^x:\\\\&#10;\text{Using }\int u\,dv=uv-\int v\,du:\\\\&#10;I=\frac{1}{2}(e^x\sin(2x)-\int e^x(2\cos(2x))dx)\\\\&#10;2I=e^x\sin(2x)-2\underbrace{\int e^x\cos(2x)dx}_{I_2}

Looking for I_2:

\text{If}~u=\cos(2x)\to du=-2\sin(2x)dx~\text{and}~dv=e^xdx\to v=e^x:\\\\&#10;I_2=e^x\cos(2x)-\int e^x(-2\sin(2x))dx\\\\ I_2=e^x\cos(2x)+2\int e^x(\sin(2x))dx\\\\  I_2=e^x\cos(2x)+2\int e^x(2\sin(x)\cos(x))dx\\\\ I_2=e^x\cos(2x)+4\int e^x(\sin(x)\cos(x))dx=e^x\cos(2x)+4I

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2I=e^x\sin(2x)-2I_2\iff\\\\2I=e^x\sin(2x)-2(e^x\cos(2x)+4I)\iff\\\\&#10;2I=e^x\sin(2x)-2e^x\cos(2x)-8I\iff\\\\&#10;10I=e^x\sin(2x)-2e^x\cos(2x)\iff\\\\&#10;I=\dfrac{e^x}{10}(\sin(2x)-2\cos(2x))\\\\&#10;\boxed{\int e^x(\sin(x)\cos(x))dx=\dfrac{e^x}{10}(\sin(2x)-2\cos(2x))+C}
6 0
3 years ago
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