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Elenna [48]
2 years ago
13

What is the volume of the right cylinder?

Mathematics
1 answer:
Vesnalui [34]2 years ago
7 0
The answer would be C hope this helps;)
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What is the value of 56.13?
SpyIntel [72]

Answer:

The value is Approximately 56

8 0
3 years ago
Read 2 more answers
Find the surface area of x^2+y^2+z^2=9 that lies above the cone z= sqrt(x^@+y^2)
Mashcka [7]
The cone equation gives

z=\sqrt{x^2+y^2}\implies z^2=x^2+y^2

which means that the intersection of the cone and sphere occurs at

x^2+y^2+(x^2+y^2)=9\implies x^2+y^2=\dfrac92

i.e. along the vertical cylinder of radius \dfrac3{\sqrt2} when z=\dfrac3{\sqrt2}.

We can parameterize the spherical cap in spherical coordinates by

\mathbf r(\theta,\varphi)=\langle3\cos\theta\sin\varphi,3\sin\theta\sin\varphi,3\cos\varphi\right\rangle

where 0\le\theta\le2\pi and 0\le\varphi\le\dfrac\pi4, which follows from the fact that the radius of the sphere is 3 and the height at which the sphere and cone intersect is \dfrac3{\sqrt2}. So the angle between the vertical line through the origin and any line through the origin normal to the sphere along the cone's surface is

\varphi=\cos^{-1}\left(\dfrac{\frac3{\sqrt2}}3\right)=\cos^{-1}\left(\dfrac1{\sqrt2}\right)=\dfrac\pi4

Now the surface area of the cap is given by the surface integral,

\displaystyle\iint_{\text{cap}}\mathrm dS=\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dv\,\mathrm du
=\displaystyle\int_{u=0}^{u=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}9\sin v\,\mathrm dv\,\mathrm du
=-18\pi\cos v\bigg|_{v=0}^{v=\pi/4}
=18\pi\left(1-\dfrac1{\sqrt2}\right)
=9(2-\sqrt2)\pi
3 0
2 years ago
What is the change in elevation from -87.2 Feet to 33.6 Feet?
allochka39001 [22]

Answer:

120.8 feet

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The systolic blood pressure of adults in the USA is nearly normally distributed with a mean of 122 and standard deviation of 22
marin [14]

Answer: 4.27% of adults in the USA have stage 2 high blood pressure.

Step-by-step explanation:

Let x be a random variable that denotes a person with high blood pressure .

Given: Average blood pressure: \mu=122

Standard deviation: \sigma=22

Someone qualifies as having Stage 2 high blood pressure if their systolic blood pressure is 160 or higher.

The probability that an adult in the USA have stage 2 high blood pressure:

P(x\geq160)=P(\dfrac{x-\mu}{\sigma}}\geq\dfrac{160-122}{22})\\\\=P(z\geq1.72)\ \ \ [z=\dfrac{x-\mu}{\sigma}]\\\\=1-P(z

Hence, 4.27% of adults in the USA have stage 2 high blood pressure.

6 0
2 years ago
Someone help ASAP will give brainliest
bogdanovich [222]
The 3rd answer, is correct.
3 0
3 years ago
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