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andrezito [222]
3 years ago
11

Martin ordered a pizza with a 12-inch diameter.Ricky ordered a pizza with a 16-inch diameter. What is the approximate difference

in area of the two pizzas in square inches
Mathematics
1 answer:
il63 [147K]3 years ago
3 0

Answer:

The surface difference of the two pizzas is 113.14 in²

Step-by-step explanation:

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What is being done to the variable in the equation 3 + g = -9?
almond37 [142]

Answer:

its A

Step-by-step explanation:

not gonna explain it cause I dont have to ._. plus it wasnt that hard

4 0
3 years ago
Pleaseeee help asap !! i’ll mark brainliest
Blizzard [7]

Answer:

Step-by-step explanation:

C, (1,7)

6 0
3 years ago
A photo collage consists of seven equal-sized square photos arranged in a row to form a rectangle. If the total area of the coll
andrezito [222]

Given:

Seven equal-sized square photos arranged in a row to form a rectangle.

Total area of the collage is 567 square inches.

To find:

The length of the collage.

Solution:

Let the side of each square be x inches.

Seven equal-sized square photos arranged in a row to form a rectangle.

So, length of rectangle is 7x and width is x.

Area of rectangle is

Area=Length\times width

567=7x\times x

567=7x^2

\dfrac{567}{7}=x^2

81=x^2

Taking square root on both sides, we get

x=\pm \sqrt{81}

x=\pm 9

Side cannot be negative. So, x=9 inches.

Now,

Width = 9 inches

Length = 7(9) = 63 inches

Therefore, the length of the rectangle is 63 inches.

7 0
4 years ago
use green's theorem to evaluate the line integral along the given positively oriented curve. c 9y3 dx − 9x3 dy, c is the circle
Rina8888 [55]

The line integral along the given positively oriented curve is -216π. Using green's theorem, the required value is calculated.

<h3>What is green's theorem?</h3>

The theorem states that,

\int_CPdx+Qdy = \int\int_D(\frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y})dx dy

Where C is the curve.

<h3>Calculation:</h3>

The given line integral is

\int_C9y^3dx-9x^3dy

Where curve C is a circle x² + y² = 4;

Applying green's theorem,

P = 9y³; Q = -9x³

Then,

\frac{\partial P}{\partial y} = \frac{\partial 9y^3}{\partial y} = 27y^2

\frac{\partial Q}{\partial x} = \frac{\partial -9x^3}{\partial x} = 27x^2

\int_C9y^3dx-9x^3dy = \int\int_D(-27x^2 - 27y^2)dx dy

⇒ -27\int\int_D(x^2 + y^2)dx dy

Since it is given that the curve is a circle i.e., x² + y² = 2², then changing the limits as

0 ≤ r ≤ 2; and 0 ≤ θ ≤ 2π

Then the integral becomes

-27\int\limits^{2\pi}_0\int\limits^2_0r^2. r dr d\theta

⇒ -27\int\limits^{2\pi}_0\int\limits^2_0 r^3dr d\theta

⇒ -27\int\limits^{2\pi}_0 (r^4/4)|_0^2 d\theta

⇒ -27\int\limits^{2\pi}_0 (16/4) d\theta

⇒ -108\int\limits^{2\pi}_0 d\theta

⇒ -108[2\pi - 0]

⇒ -216π

Therefore, the required value is -216π.

Learn more about green's theorem here:

brainly.com/question/23265902

#SPJ4

3 0
2 years ago
Instructions: Use proportions to answer each of these word problems. You can use a calculator.
Mekhanik [1.2K]
If i do all that, you need to give me more point bc this needs more points
3 0
3 years ago
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