A photo collage consists of seven equal-sized square photos arranged in a row to form a rectangle. If the total area of the coll
1 answer:
Given:
Seven equal-sized square photos arranged in a row to form a rectangle.
Total area of the collage is 567 square inches.
To find:
The length of the collage.
Solution:
Let the side of each square be x inches.
Seven equal-sized square photos arranged in a row to form a rectangle.
So, length of rectangle is 7x and width is x.
Area of rectangle is
Taking square root on both sides, we get
Side cannot be negative. So, x=9 inches.
Now,
Width = 9 inches
Length = 7(9) = 63 inches
Therefore, the length of the rectangle is 63 inches.
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We assume the lunch prices we observe are drawn from a normal distribution with true mean and standard deviation 0.68 in dollars.
We average samples to get
.
The standard deviation of the average (an experiment where we collect 45 samples and average them) is the square root of n times smaller than than the standard deviation of the individual samples. We'll write
Our goal is to come up with a confidence interval (a,b) that we can be 90% sure contains .
Our interval takes the form of as
is our best guess at the middle of the interval. We have to find the z that gives us 90% of the area of the bell in the "middle".
Since we're given the standard deviation of the true distribution we don't need a t distribution or anything like that. n=45 is big enough (more than 30 or so) that we can substitute the normal distribution for the t distribution anyway.
Usually the questioner is nice enough to ask for a 95% confidence interval, which by the 68-95-99.7 rule is plus or minus two sigma. Here it's a bit less; we have to look it up.
With the right table or computer we find z that corresponds to a probability p=.90 the integral of the unit normal from -z to z. Unfortunately these tables come in various flavors and we have to convert the probability to suit. Sometimes that's a one sided probability from zero to z. That would be an area aka probability of 0.45 from 0 to z (the "body") or a probability of 0.05 from z to infinity (the "tail"). Often the table is the integral of the bell from -infinity to positive z, so we'd have to find p=0.95 in that table. We know that the answer would be z=2 if our original p had been 95% so we expect a number a bit less than 2, a smaller number of standard deviations to include a bit less of the probability.
We find z=1.65 in the typical table has p=.95 from -infinity to z. So our 90% confidence interval is
in other words a margin of error of
dollars
That's around plus or minus 17 cents.
By knowing the <em>blood</em> pressure and applying the <em>quadratic</em> formula, the age of a man whose normal <em>blood</em> pressure is 129 mm Hg is 40 years old.
<h3>How to use quadratic equations to determine the age of a man in terms of blood pressure</h3>
In this problem we have a <em>quadratic</em> function that models the <em>blood</em> pressure as a function of age. As the latter is known, we must use the quadratic formula to determine the former:
129 = 0.006 · A² - 0.02 ·A + 120
0.006 · A² - 0.02 · A - 9 = 0
A = 1.667 + 38.733
A = 40
By knowing the <em>blood</em> pressure and applying the <em>quadratic</em> formula, the age of a man whose normal <em>blood</em> pressure is 129 mm Hg is 40 years old.
To learn more on quadratic equations: brainly.com/question/1863222
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