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Masteriza [31]
3 years ago
5

The following table represents the highest educational attainment of all adult residents in a given city. If a resident between

the ages of 30 and 49 is randomly selected, what is the probability that she has only completed a few college studies? Round your answer to the nearest thousandth.
Mathematics
1 answer:
DanielleElmas [232]3 years ago
4 0
Not sure I am sorry for that
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Find the product of the monomial and polynomial xyz*(2x+3y^2-3z^2)
marissa [1.9K]

Answer:

2x^2yz + 3xy^3z - 3xyz^3

Step-by-step explanation:

First you must distribute:

xyz(2x) + xyz(3y^2) + xyz(-3z^2)

Then simplify:

2xyxx + 3xyzy^2 - 3xyz * z^2

And finally simplify each term:

2x^2yz + 3xy^3z - 3xyz^3

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3 years ago
HELP PLZ GUYS I BEG YOU 15 PTS ITS EASYYYYYYY!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Aliun [14]

Answer:

1) The linear equation in point and slope form is y - 67 = -4 × (x - 14)

2) The variables are;

a) The number of candies available = y

b) The number of days Jennifer eats the candies =

c) The slope, m = -4

3) Jennifer received 123 pieces of candies on Halloween

Step-by-step explanation:

The given parameters are;

The number of candies Jennifer eats everyday = 4 pieces

The number of days for which Jennifer eats the daily 4 candies = 14

The number of candies left at the end of the 14th day = 67 candies

1) We note that the rate of decrease in the number of candies = 4 candies/day

Therefore, the slope of the linear equation is m = -4

The y-intercept = The initial amount of candies Jennifer has = c = 67 + 14× 4 = 123 candies

The linear equation in point and slope form is given as follows;

y - 67 = -4 × (x - 14)

2) The variables are;

a) The y-value represents the number of candies available on a specific day

b) The x value represents the number of days Jennifer eats the candies'

c) The slope = The rate of decrease in the number of candies per day = -4

3) The number of candies Jennifer receives on Halloween is given by the y-intercept of the straight line equation as follows;

y - 67 = -4 × (x - 14)

y - 67 = -4·x + 56

y = -4·x + 56 + 67 = -4·x + 123

y = -4·x + 123

Comparing the above equation, with the general form of the straight line equation, y = m·x + c, where, the constant term, c = The y-intercept, we have;

The y-intercept of the equation y = -4·x + 123 = 123 = The initial amount of candies Jennifer received on Halloween.

6 0
3 years ago
What shows the correct substitution of the values a,b, and c from the equation 0=-3x^2-2x+6
Arlecino [84]

When dealing with a quadratic equation, you usually assign the following name to the coefficients of the variables:

ax^2+bx+c=0

So, a is the coefficient of x^2, b is the coefficient of x and c is the constant term.

In your case, the coefficient of x^2 is -3, so a=-3

The coefficient of x is -2, so b = -2

The constant term is 6, so c = 6

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The answer is 3 because the length of the box is 10, the width is 5, and the height is 3.
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