1.
5u - 2u = 3u (diff. between longest and shortest)
3u = 87cm
1u = 87cm ÷ 3 = 29cm
5u + 4u + 2u=11u
11u = 11 x 29cm = 319cm
Ans: 319cm
2.
9u = 1350
1u = 1350 ÷ 9 = 150
6u + 5u = 11u
11u = 11 x 150 = 1650
Ans: 1650
Answer:
280000lb
Step-by-step explanation:
In this question, we shall be calculating the amount of carbon iv oxide prevented from entering the atmosphere.
Generally we know that 1kwh produces 1.37 lbs of Carbon iv oxide in the atmosphere
Now, using a 100 watt light bulb daily for 8 hours, for a year, the amount of Carbon iv oxide produced will be;
100 * 1.37 * 8 * 365 = 40040 lb
Using a 30 watt CFL for 8hrs/ day for a year, we have;
30 * 1.37 * 8 * 365 = 120012 lb
Now calculating the amount of CO2 prevented, we have 40040 - 120012 = 280028 lb = 280000 after rounding up
Answer:
2
Step-by-step explanation:
5y-2x
5(2)-2(4)
10-8=2
C
the sum to infinity of a geometric series = 
where a is the first term and r the common ratio
=
= 81 × 3 = 243
5 kilometers = 5000 decimeters if that answers your question sorry ...