Answer:
There is no sufficient evidence to support the claim that the bags are underfilled
Step-by-step explanation:
We are given;
n = 27 bags
Sample mean;X = 402 gram
Population mean;μ = 404 gram
Variance = 676
We know that, standard deviation(σ) = √variance
Thus;
σ = √676
σ = 26
The hypotheses are;
Null hypothesis; H0: μ = 404
Alternative hypothesis; HA: μ < 404
Let's find the z-score from the formula;
z = (X - μ)/(√σ/n)
z = (402 - 404)/√(26/27)
z = -2.04
From the z-distribution table attached, we have a p-value of 0.02068
This is less than the significance value of 0.01 and thus we will reject the null hypothesis and conclude that there is no sufficient evidence to support the claim that the bags are underfilled
Answer:
b)A cube with side lengths of 4 feet has a volume of 64cubic feet
Step-by-step explanation:
volume=length×width×height
=4×4×4
=64feet³
Answer:
<h2>W = 16</h2>
Step-by-step explanation:
<h3>
![\sqrt[4]{W} = 2](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7BW%7D%20%20%3D%202)
</h3>
To find W raise each of the sides of the equation to the power 4 to make W stand alone
That's
<h3>
![( { \sqrt[4]{W} })^{4} = {2}^{4}](https://tex.z-dn.net/?f=%28%20%7B%20%5Csqrt%5B4%5D%7BW%7D%20%7D%29%5E%7B4%7D%20%20%3D%20%20%7B2%7D%5E%7B4%7D%20)
</h3>
We have
W = 2⁴
We have the final answer as
<h3>W = 16</h3>
Hope this helps you
Looking at the set, we are given 18 elements. 17 is prime; it has only two factors: 1 and 17, since 1•17=17. So, the question is really asking what is the probability the numbers 1 or 17 is chosen. As mentioned earlier, 17 is prime, so there are two possible choices: 1 and 17.
P (probability) = possible outcomes / total outcomes
It is important to note that these events are “or” events, meaning that the probability can only be determined by choosing a 1 or a 17; you can’t randomly chose a 1 and 17 at the same time. So, the formula is:
P(A or B) = P(A) + P(B)
All this is saying is that given two possible outcomes, the probability occurs independent of each event; they don’t occur at the same time.
P(1 or 17) = P(1)/18 + P(1)/18
P(1 or 17) = 2/18
Since 17 is prime, it’s two and only factors are 1 and 17. The probability of randomly choosing a 1 or 17 is 2/18, meaning that there are 2 elements in the set out of a possible 18 elements that can be randomly chosen.
2/18 simplifies to 1/9
So, your answer is 1/9
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