Let the number<span> be H T O. Ones digit = O Given that. O =10−5 ⇒ O =5. Also is given that tens digit T is 2 </span>more than<span> ones digit O ⇒ tens digit T = O +2=5+2=7. ∴ The </span>number<span> is. H 75. Given also is that "</span>number<span> is </span>less<span> than </span>200<span> and </span>greater than 100<span> " ⇒ H can take value only =1. We get our </span>number<span>as 175.</span>
It is A'C' because when the figure is dilatted the corresponding figure has " by it.
hopes this helps :)
The answer is 6.3 bc the perimeter would be all of them added together
1. The area of the full rectangle is 21 * 28 = 588. We will need this later.
Like you drew, there is an imaginary triangle missing. We can find the dimensions of it by subtracting from the given information. The shorter leg of it is 21 - 12 = 9, the longer leg is 28 - 14 = 14.
Now we find the area of the triangle. Area of a triangle is 1/2 * base * height. So 1/2 * 9 * 14 = 1/2 * 126 = 63.
Now we do the full area of 588 minus the area of the missing triangle piece.
588 - 63 = 525 ft²
2. Do the area of the rectangle and then this time add on the area of the triangle. 7 * 15 = 105. Area of the triangle = 1/2 * 2 * 7 = 1/2 * 14 = 7.
105 + 7 = 112 in²
$68 is discounted from the regular price.
To find this, you first divide 80% by 100 to get 0.8 (the decimal form of the percentage). Then, simply multiply 0.8 by 85 (or vise verse) to get $68. Since the question is asking for how much is discounted from the regular price, the final answer would be $68.
I hope this helps!
