Answer:
The current of the river has a speed of 3 miles per hour
Step-by-step explanation:
Let's call v the speed of the boat in calm waters.
We know that:
![v = \frac{d}{t}](https://tex.z-dn.net/?f=v%20%3D%20%5Cfrac%7Bd%7D%7Bt%7D)
Where d is the distance in miles and t is the time
When the boat travels down we have to:
![d=2.4\ miles](https://tex.z-dn.net/?f=d%3D2.4%5C%20miles)
If s is the speed at which the boat travels downstream and c is the speed of the river then
![s=(v+c)](https://tex.z-dn.net/?f=s%3D%28v%2Bc%29)
And
![t=\frac{d}{s}\\\\t=\frac{d}{v+c}\\\\t=\frac{2.4}{21+c}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7Bd%7D%7Bs%7D%5C%5C%5C%5Ct%3D%5Cfrac%7Bd%7D%7Bv%2Bc%7D%5C%5C%5C%5Ct%3D%5Cfrac%7B2.4%7D%7B21%2Bc%7D)
When the boat travels upstream we have to:
![d=1.8\ miles](https://tex.z-dn.net/?f=d%3D1.8%5C%20miles)
![s=(v-c)](https://tex.z-dn.net/?f=s%3D%28v-c%29)
![t=\frac{d}{s}\\\\t=\frac{d}{v-c}\\\\t=\frac{1.8}{21-c}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7Bd%7D%7Bs%7D%5C%5C%5C%5Ct%3D%5Cfrac%7Bd%7D%7Bv-c%7D%5C%5C%5C%5Ct%3D%5Cfrac%7B1.8%7D%7B21-c%7D)
We know that the time he navigate upstream is the same time he navigate downstream
Then:
![\frac{2.4}{21+c}=\frac{1.8}{21-c}](https://tex.z-dn.net/?f=%5Cfrac%7B2.4%7D%7B21%2Bc%7D%3D%5Cfrac%7B1.8%7D%7B21-c%7D)
We solve the equation for c
![2.4*(21-c)=(21+c)*1.8](https://tex.z-dn.net/?f=2.4%2A%2821-c%29%3D%2821%2Bc%29%2A1.8)
![50.4-2.4c=37.8+1.8c](https://tex.z-dn.net/?f=50.4-2.4c%3D37.8%2B1.8c)
![50.4-37.8=1.8c+2.4c](https://tex.z-dn.net/?f=50.4-37.8%3D1.8c%2B2.4c)
![4.2c=12.6](https://tex.z-dn.net/?f=4.2c%3D12.6)
![c=\frac{12.6}{4.2}](https://tex.z-dn.net/?f=c%3D%5Cfrac%7B12.6%7D%7B4.2%7D)
![c=3\ miles\ per\ hour](https://tex.z-dn.net/?f=c%3D3%5C%20miles%5C%20per%5C%20hour)