The steps to use to construct a frequency distribution table using sturge’s approximation is as below.
<h3>How to construct a frequency distribution table?</h3>
The steps to construct a frequency distribution table using Sturge's approximation are as follows;
Step 1: Find the range of the data: This is simply finding the difference between the largest and the smallest values.
Step 2; Take a decision on the approximate number of classes in which the given data are to be grouped. The formula for this is;
K = 1 + 3.322logN
where;
K= Number of classes
logN = Logarithm of the total number of observations.
Step 3; Determine the approximate class interval size: This is obtained by dividing the range of data by the number of classes and is denoted by h class interval size
Step 4; Locate the starting point: The lower class limit should take care of the smallest value in the raw data.
Step 5; Identify the remaining class boundaries: When you have gotten the lowest class boundary, then you can add the class interval size to the lower class boundary to get the upper class boundary.
Step 6; Distribute the data into respective classes:
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Answer:
Part A
C = $.85p
For 2 pounds , the charge is $1.70
Part B
C = $.05 * p
Step-by-step explanation:
Part A
Cost = charge per pound * pounds
We know the charge per pound is $.85
C = $.85 * p
We want to ship 2 pounds
C = .85*2
C = 1.70
Part B
Cost = charge per pound * pounds
We know the charge per pound is now $.05
C = $.05 * p
Answer:

Step-by-step explanation:
The question calls requires one to get the product of the given time. Since first debate lasted for :

-and the second lasted
times more than the first then the second took then the first step will involve converting the mixed fractions into improper fraction which will be:

-Now multiplying
hrs
Answer:
t=+4.06
Step-by-step explanation:
when the baseball hits the ground, the height will be 0.
h=0we are given that h=−16t2+64t+4.
this means that the height is 0 when −16t2+64t+4=0.−16t2+64t+4=0divide both sides by 4:−4t2+16t+1=04=0−4t2+16t+1=0 can be solved using the quadratic formula:t=−b±√b2−4ac2a, where at2+bt+c=0.at2+bt+c=−4t2+16t+1a=−4,b=16,c=1t=−b+√b2−4ac2aor−b−√b2−4ac2a−b+√b2−4ac2a=−16+√272−8=−0.06..−b−√b2−4ac2a=−16−√272−8=4.06 (3s.f.)we have 2 values for t:−0.06 and 4.06.
since time cannot be negative, only the positive value can be taken.
this is 4.06, to 3 significant figures.the time taken is 4.06 seconds.