Hello there,
The equation that is give to us is as follows:
- -1 = 5 +
In order to solve for x we would first subtract 5 from both sides and then multiply by 6:
This means that x would equal to -1 given the equation above.
Hope I helped,
Amna
The total of the road is 4800 m long. 4800-1440=3360m
We subtract what they have yet to cover from the total to get what they have covered.
So in 30 days they covered 3360 metres.
3660/30 (3660 is divided into 30 equal groups) = 122m
On average they covered 122 metres per day.
Answer:
Given argument is valid
Step-by-step explanation:
In venn diagram
M=Mammals
R=Reptiles
G=Gators
Given that
No mammals are reptiles ,So in the diagram we indicates by cross sign(x).Also given that some reptiles are gators ,so venn diagram of reptiles and gators will cross each other.
But from the above statement we can say that those gators are reptiles can not be mammals but those are not reptiles they can be mammals.Hence some gators are not mammals.
So given argument is valid
Answer:
0.0319
Step-by-step explanation:
To approximate this probability, we shall be using the Bernoulli approximation of the Binomial distribution.
Let p = probability of selecting a reference book = 65% = 0.65
Let q = probability of selecting other books= 1-p = 1-0.65 = 0.35
Now, we want to find the probability that all of these 8 books to be re-shelved are reference book.
We set up the probability as follows;
P(X = 8) = 8C8 •p^8•q^0
P(X = 8) = 1 * (0.65)^8 * (0.35)^0
P(X = 8) = 0.031864481289 which is 0.0319 to 4 decimal places
The confidence interval for confidence level of
is

where
is the sample mean,
is the critical value for the given confidence level,
is the standard deviation of the population, and
is the sample size. The margin of error is the
term.
a) For a confidence level of
, we have
. So in order to have a margin of error of at most 25 points, we have

so Raina should collect a sample of at least 269 students.
b) A confidence interval with a higher confidence level would more closely approximate and reflect the population, so it stands to reason that Luke should collect a larger sample than Raina to meet his 99% confidence spec.
c) For a confidence level of
, we have
. Then the margin of error would at most satisfy

so that Luke should collect a sample of at least 666 students.