The first one is correct.
There is a VERY simple way you can do this
Here is how.
It's called the "Butterfly Method" (IDK if anyone calls it that, but I do!)
So basically, you look at the numerator for one of your numbers, and the denominator of the other number, and you multiply them! So...
1/7, you would take the seven...
1/4, and multiply it by the one...
so 7×1
and you get seven!
Then you do...
1/7, take the one...
1/4, take the four...
so 1×4
and you get four!
Whichever one is bigger (or smaller, but only if you are trying to find out which fraction is smaller...) is your answer!
Hope this helped!!!!!!!!!!!!!!
Let us say that:
a = ones
b = fives
c = twenties
So that the total money is:
1 * a + 5 * b + 20 * c = 229
=> a + 5b + 20c = 229 -->
eqtn 1
We are also given that:
c = a – 5 -->
eqtn 2
a + b + c = 30 -->
eqtn 3
Rewriting eqtn 3 in terms of b:
b = 30 – a – c
Plugging in eqtn 2 into this:
b = 30 – a – (a – 5)
b = 35 – 2a -->
eqtn 4
Plugging in eqtn 2 and 4 into eqtn 1:
a + 5(35 – 2a) + 20(a – 5) = 229
a + 175 – 10a + 20a – 100 = 229
11a = 154
a = 14
So,
b = 35 – 2a = 7
c = a – 5 = 9
Therefore there are 14 ones, 7 fives, and 9 twenties.
Answer:
The parcel with weight less than 20.14 pounds are 99% of all parcels under the surcharge weight.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 12 pounds
Standard Deviation, σ = 3.5 pounds
We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.
Formula:
We have to find the value of x such that the probability is 0.99
Calculation the value from standard normal z table, we have,
Thus, parcel with weight less than 20.14 pounds are 99% of all parcels under the surcharge weight.
The probability of rolling factors of 4 are 4/1 or 2/1
