Answer:
Height of the fighter plane =1.5km=1500 m
Speed of the fighter plane, v=720km/h=200 m/s
Let be the angle with the vertical so that the shell hits the plane. The situation is shown in the given figure.
Muzzle velocity of the gun, u=600 m/s
Time taken by the shell to hit the plane =t
Horizontal distance travelled by the shell =u
x
t
Distance travelled by the plane =vt
The shell hits the plane. Hence, these two distances must be equal.
u
x
t=vt
u Sin θ=v
Sin θ=v/u
=200/600=1/3=0.33
θ=Sin
−1
(0.33)=19.50
In order to avoid being hit by the shell, the pilot must fly the plane at an altitude (H) higher than the maximum height achieved by the shell for any angle of launch.
H
max
=u
2
sin
2
(90−θ)/2g=600
2
/(2×10)=16km
The answer would be 1/3
as in C O O K I E there are two O's out of 6 letters, so:
2/6 and this is simplified to 1/3
Mass in science is like weight. Everything is basically mass, you are mass!
This is a proportion question. We can express this as an equation where the answer is
x:
=
From there, you can just cross-multiply and divide to get:
A tenth of 250 is 25, so this is roughly
or
, so it'll be approximately 1.7 inches on the map.
