Question

Find an equation of the line that contains the point (-1,3) and is parallel to the line x+3y=6.

Answer 1

Answer:

Step-by-step explanation:

3y = -x + 6

y = -1/3x + 2

y - 3 = -1/3(x + 1)

y - 9/3 = -1/3x - 1/3

y = -1/3x + 8/3

Answer 2

Answer:

x - 8 = -3y

Step-by-step explanation:

x + 3y = 6

Convert to y = mx + b form, and we get: x - 6 = -3y

Remember m is our slope, and in this case, it is simply one.

Because the line we're solving for is parallel, it must have the same slope.

y = 1x + b, we just have to solve for b now.

This is done by plugging in our points, which looks like: -1  + b = -3 x 3

simplify: -1 + b = -9, b = -8

Combining what we know yields: x - 8 = -3y

Hope this helps :)