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VARVARA [1.3K]
3 years ago
12

What is the interquartile range?

Mathematics
1 answer:
Wewaii [24]3 years ago
6 0

Step-by-step explanation:

interquartile \: range =  \frac{1}{2} (Q _{3} - Q _{1} ) \\  =  \frac{1}{2} (38 - 34) \\  =  \frac{1}{2} (4) \\  = 2

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The system of equations y = one-fourth x minus 5 and y = negative one-half x minus 3 is shown on the graph below. On a coordinat
anyanavicka [17]

Answer:

The x-value is between 2 and 3, and the y-value is between -4 and -5

Step-by-step explanation:

The plot of the equations:

y = 1/4x - 5 (red)

y = -1/2x - 3 (blue)

is shown in the figure attached.

The solution to the system is found at the intersection point. In this case, the solution is x = 2.667 and y = -4.333

3 0
3 years ago
What is the mean? Round to the nearest tenth if needed.
Ray Of Light [21]

Answer: i think this is it

the answer would be 3

Step-by-step explanation:

It says something like this: Multiply each value by the frequency of that value:  1*7, 2*1, etc. I'll let you write down the rest.

Divide by the sum of the frequencies, 7 + 1

5 0
4 years ago
Solve for x.<br> 4x - y= -11
balandron [24]

Step-by-step explanation:

4x - y =  - 11

4x =  - 11 + y

4x = y - 11

x =  \frac{y - 11}{4}

3 0
1 year ago
Find the sum and choose the correct answer.
MrRa [10]
Hi

2n³ + 4n² - 7 + (-n³ - 8n - 2) = 2n³ - n³ + 4n² - 8n - 7 - 2 

n³ + 4n² - 8n - 9

Answer: n³ + 4n² - 8n - 9
8 0
3 years ago
Read 2 more answers
Assume the number of typo errors on a single page of a book follows Poisson distribution with parameter 1=3. Calculate the proba
asambeis [7]

Answer:

(i). 0.03981

(ii).0.0048

Step-by-step explanation:

The probability density function of Poisson distribution is:

P(X=x,\lambda)=\frac{e^{-\lambda}\lambda^x}{x!} \; \;\;\,\; x=0,1,2,...

Consider <em>X</em> is a number of typos error on a single page of a book and <em>X</em> follows the Poisson distribution with \lambda = \dfrac{1}{3}

(i) Exactly two typos:

            \begin{aligned}P(X = 2,\frac{1}{3})&=\frac{e^{-\frac{1}{3}}\frac{1}{3}^{2}}{2!}\\&=\frac{e^{-\frac{1}{3}}}{18}\\&=0.03981\end{aligned}

(ii) Two or more typos:

       \begin{aligned}P(X\geq2,\frac{1}{3})&=1-[P(X=0)+P(X=1)+P(X+2)]\\&=1-[0.7165+0.2388+0.03981]\\&=1-0.9952\\&=0.0048\end{aligned}

7 0
4 years ago
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