Multiply total hours worked by pay rate:
20.5 x $13.75 = $281.88
The "sample" with "mean absolute deviation" indicate about a sample mean absolute deviation is being used as an estimator of the mean absolute deviation of a population
- Mean of the sample MAD=3.3
- Population MAD =6.4
<h3>What does this indicate about a sample mean absolute deviation used as an estimator of the mean absolute deviation of a population?</h3>
Generally, The MAD measures the average dispersion around the mean of a given data collection.

In conclusion, for the corresponding same to mean
the sample mean absolute deviation
7,7 ↔ 0
7,21 ↔ 7
7,22 ↔ 7.5
21,7 ↔ 7
21,21 ↔ 0
21,22 ↔ 0.5
22,7 ↔ 7.5
Therefore
- Mean of the sample MAD=3.3
- Population MAD =6.4
Read more about mean absolute deviation
brainly.com/question/10528201
#SPJ1
Answer:
Step-by-step explanation:
b. p(10.5<x<11.2)= p(x<11.2)-p(x<10.5)
p(x<11.2)= (11.2-9.7)/1 = 1.5 = 0.9332
p(x<10.5)= (10.5-9.7)/1= .8= 0.7881
.9332-0.7881= .1451
c. 9.7-.253, 9.7+.253
9.447, 9.953
Answer:
y=-4-3x
Step-by-step explanation:
y = -3x - 4
y = -3x + (-4)
y = -4 + 3x
y = -4 - 3x