Answer:
225 burgers
Step-by-step explanation:
522-72=450
450/2=225
(a) * (a+1) = 420
a^2 + a = 420
a^2 + a - 420 = 0
(a+21)(a-20) = 0
a = -21 OR 20
The two integers can be -21 and -20, OR 20 and 21.
Answer:
4 ....,..........................................
Answer:
a) 30 kangaroos in 2030
b) decreasing 8% per year
c) large t results in fractional kangaroos: P(100) ≈ 1/55 kangaroo
Step-by-step explanation:
We assume your equation is supposed to be ...
P(t) = 76(0.92^t)
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a) P(10) = 76(0.92^10) = 76(0.4344) = 30.01 ≈ 30
In the year 2030, the population of kangaroos in the province is modeled to be 30.
__
b) The population is decreasing. The base 0.92 of the exponent t is the cause. The population is changing by 0.92 -1 = -0.08 = -8% each year.
The population is decreasing by 8% each year.
__
c) The model loses its value once the population drops below 1/2 kangaroo. For large values of t, it predicts only fractional kangaroos, hence is not realistic.
P(100) = 75(0.92^100) = 76(0.0002392)
P(100) ≈ 0.0182, about 1/55th of a kangaroo
Given:
The number of male professors = 15.
The number of female professors = 9.
The number of male teaching assistants = 6.
The number of female teaching assistants = 12.
A person is selected randomly from the group.
Required:
We need to find the probability that the selected person is a professor or a male.
Explanation:
The total number of people in the group = 15+9+6+12 = 42
n(S) =The total number of people in the group
Let A be the event that the selected person is a professor or a male.
The number of people who are professors or male = 15+9+6 = 30
n(A)= The number of people who are professors or male.
Let P(A) be the probability that the selected person is a professor or a male.
Final answer:
The probability that the selected person is a professor or a male is 5/7.
