Question

What is the equation of aline that passes through the point (4,-8) and has a slope of -1/2?

Answer 1

Answer:

The equation of the line will be:

$y=-\frac{1}{2}x-6$

Step-by-step explanation:

Given

• slope = m = -1/2

• point (4, -8)

Point slope form:

$y-y_1=m\left(x-x_1\right)$

substituting the values m = -1/2 and the point (4,-8)

$y-\left(-8\right)=\frac{-1}{2}\left(x-4\right)$

$y+8=\frac{-1}{2}\left(x-4\right)$

subtract 8 from both sides

$y+8-8=\frac{-1}{2}\left(x-4\right)-8$

$y=-\frac{1}{2}x-6$

Therefore, the equation of the line will be:

$y=-\frac{1}{2}x-6$