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mojhsa [17]
3 years ago
7

Can some one help me please

Mathematics
1 answer:
frutty [35]3 years ago
6 0
I believe The answer is B
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Help! Given that tanθ=-1, what is the value of secθ, for 3π/2<θ<2π?
user100 [1]

Answer:  Choice B)  \sqrt{2}

Work Shown:

\sec^2(\theta) = \tan^2(\theta) + 1\\\\\sec^2(\theta) = (\tan(\theta))^2 + 1\\\\\sec^2(\theta) = (-1)^2 + 1\\\\\sec^2(\theta) = 2\\\\\sec(\theta) = \sqrt{2}\\\\

Note: secant is positive in quadrant Q4, when theta is between 3pi/2 radians and 2pi radians (270 degrees and 360 degrees). So that's why we don't consider the minus form of the plus minus.

5 0
3 years ago
Complete the table for the given rule. Rule: y = x + 3
devlian [24]

Answer:

Step-by-step explanation:

since there is no table included with the question I'm concluding that you need to find values of y using values of x, simply substitute the x values in the equation and you'll get the y value like this

if x = 1 y = 4

4 0
3 years ago
Read 2 more answers
Triangle MNP is dilated according to the rule DO,1.5 (x,y)Right arrow(1.5x, 1.5y) to create the image triangle M'N'P, which is n
Vikki [24]

Given:

The vertex of a triangle MNP are M(-4, 6), N(2, 6), and P(-1, 1).

The rule of dilation is:

(x,y)\to (1.5x,1.5y)

The image of triangle MNP after dilation is M'N'P'.

To find:

The coordinates of the endpoints of segment M'N'.

Solution:

The end points of MN are M(-4, 6) and N(2, 6).

The rule of dilation is:

(x,y)\to (1.5x,1.5y)

Using this rule, we get

M(-4,6)\to M'(1.5(-4),1.5(6))

M(-4,6)\to M'(-6,9)

And,

N(2,6)\to N'(1.5(2),1.5(6))

N(2,6)\to N'(3,9)

The endpoints of M'N' are M'(-6, 9) and N'(3, 9).

Therefore, the correct option is B.

8 0
3 years ago
The total pay for 12 hours of work at a base rate of (p) per hour plus a temporary raise of $2.50 per hour. How would I write th
Naddika [18.5K]
12P+2.50 HOPE THIS HELPS
4 0
3 years ago
7.5 x 7.5 x (6.084−5.44)
Mars2501 [29]

Hello!

Answer:

36.225

Step-by-step explanation:

Hope this helps!

8 0
3 years ago
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