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2 years ago

15

I have a spinner that is divided into 4 equal sections colored red, blue, green, and yellow .If I spin the spinner twice ,What i

s the probability that the spinner will land on yellow both times ?

2 answers:

Alex777 [14]2 years ago

8 0

ANSWER:

1/4 that is the answer to your question

andriy [413]2 years ago

4 0

Answer:

is of 25%

Step-by-step explanation:

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I need to know the minus 2 ounces

Gennadij [26K]

Answer:

Step-by-step explanation:

10 is your answer

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2 years ago

Please help me answer this question

sukhopar [10]

Answer:

her first mistake was on line 3.

line 1: 80 + [2(3 1/2 + 1 1/2)]

line 2: 80 + [2(5)]

line 3: 80 + 10

line 4: 90

Step-by-step explanation:

on line 3 she added 80 + 2, but she should have multiplied 2 by 5. the correct steps would be:

line 1: 80 + [2(3 1/2 + 1 1/2)]

line 2: 80 + [2(5)]

line 3: 80 + 10

line 4: 90

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3 years ago

What are the solutions of 3x^2-x+4=0

guajiro [1.7K]

3x² -x+4=0

We can use quadratic formula
a=3, b= -1, c=4
$x= \frac{-b+/- \sqrt{b^{2}-4ac} }{2a} 
\\ \\ x= \frac{1+/- \sqrt{1-4*3*4} }{2*3} 
\\ \\ x = \frac{1+/- \sqrt{-47} }{6} 

This equation does not have real roots, it has only 2 imaginary roots.$

$x= \frac{1+ \sqrt{47}i }{6} 
\\ \\ x= \frac{1- \sqrt{47}i }{6}$

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3 years ago

What is the measure of space inside a suitcase?

77julia77 [94]

Answer:

Linear inches

Step-by-step explanation:

or really, any linear dimension – simply refer to the sum total of your bag's length, width and depth.

4 0

2 years ago

Read 2 more answers

A professor has learned that three students in his class of 20 will cheat on the final exam. He decides to focus his attention o

balu736 [363]

Answer:

a

$P(X \ge 1) = 0.509$

b

$P(X \ge 1) = 0.6807$

Step-by-step explanation:

From the question we are told that

The number of students in the class is N = 20 (This is the population )

The number of student that will cheat is k = 3

The number of students that he is focused on is n = 4

Generally the probability distribution that defines this question is the Hyper geometrically distributed because four students are focused on without replacing them in the class (i.e in the generally population) and population contains exactly three student that will cheat.

Generally probability mass function is mathematically represented as

$P(X = x) = \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}$

Here C stands for combination , hence we will be making use of the combination functionality in our calculators

Generally the that he finds at least one of the students cheating when he focus his attention on four randomly chosen students during the exam is mathematically represented as

$P(X \ge 1) = 1 - P(X \le 0)$

Here

$P(X \le 0) = \frac{ ^{3} C_0 * ^{20 - 3} C_{4- 0}}{ ^{20}C_4}$

$P(X \le 0) = \frac{ ^{3} C_0 * ^{17} C_{4}}{ ^{20}C_4}$

$P(X \le 0) = \frac{ 1 * 2380}{ 4845}$

$P(X \le 0) = 0.491$

Hence

$P(X \ge 1) = 1 - 0.491$

$P(X \ge 1) = 0.509$

Generally the that he finds at least one of the students cheating when he focus his attention on six randomly chosen students during the exam is mathematically represented as

$P(X \ge 1) = 1 - P(X \le 0)$

$P(X \ge 1) =1- [ \frac{^{k}C_x * ^{N-k}C_{n-x}}{^{N}C_n}]$

Here n = 6

So

$P(X \ge 1) =1- [ \frac{^{3}C_0 * ^{20 -3}C_{6-0}}{^{20}C_6}]$

$P(X \ge 1) =1- [ \frac{^{3}C_0 * ^{17}C_{6}}{^{20}C_6}]$

$P(X \ge 1) =1- [ \frac{1 * 12376}{38760}]$

$P(X \ge 1) =1- 0.3193$

$P(X \ge 1) = 0.6807$

5 0

3 years ago